Modifying this code to read 8 inputs onto one single line?

[CodingIsHard17]

I am trying to modify this code to receive any amount of input, rather than just 10, but also giving the user a code word like "DONE" to end the program. However, get 8 of those inputs onto a single line rather than just one per line?

#include <iostream>
#include <sstream>
#include <string>
#include <vector>
#include <cctype>
using std::cin;
using std::cout;
using std::endl;
using std::istringstream;
using std::string;
using std::vector;
using namespace std;

int main()
{
    string s;
    vector<string>v;
    
    for(int i = 0; i < 10; ++i)
    {
        cin >> s;
        v.push_back(s);
    }
    for(int i = 0; i < v.size(); ++i)
    {
        for(int j = 0; j < v[i].size(); ++j)
        {
            if(islower(v[i][j]))
            {
                v[i][j] = toupper(v[i][j]);
            }
        }
    }
    
    for(int i = 0; i < v.size(); ++i)
    {
        cout << v[i] << "\n";
    }
    return 0;
}

[Ganado]

Any # of input:

vector <string> v;
std::cout << "enter amount: ";
int amount;
std::cin >> amount;
for (int i = 0; i < amount; i++)
{
    cin >> s;
    v.push_back(s);
}

8 per line:

    for(int i = 0; i < v.size(); ++i)
    {
        cout << v[i];
        if (i % 8 == 7)
            cout << '\n';

    }

% (modulus) operator is basically like taking the remainder.
0 % 3 == 0
1 % 3 == 1
2 % 3 == 2 (new line after)
3 % 3 == 0
4 % 3 == 1
5 % 3 == 2 (new line after)
6 % 3 == 0
...

[CodingIsHard17]

#include <iostream>
#include <sstream>
#include <string>
#include <vector>
#include <cctype>
using std::cin;
using std::cout;
using std::endl;
using std::istringstream;
using std::string;
using std::vector;
using namespace std;

int main()
{
    string s;
    vector<string>v;
    std::cout << "Please enter amount needed in string: ";
    
    int amount;
    std::cin >> amount;
    
    for(int i = 0; i < amount; i++)
    {
        cin >> s;
        v.push_back(s);
    }
    for(int i = 0; i < v.size(); ++i)
    {
        for(int j = 0; j < v[i].size(); ++j)
        {
            if(islower(v[i][j]))
            {
                v[i][j] = toupper(v[i][j]);
            }
        }
    }
    
    for(int i = 0; i < v.size(); ++i)
    {
        cout << v[i];
        if (i % v.size() == v.size() -1)
            cout << "\n";
    }
    return 0;
}

Please enter amount needed in string: 3
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