Set char 1 = char 2. What is syntax?

[Steve02]

I've been searching for this but found no examples or discussion.

I'm trying to input the value to one char using the value from another, like:

   char input1[30] = "Input One"; //One of many values
   char subject[30] = input1;  // Push value to Subject 

My subject is a value I'd like to fill dynamically at runtime based on an input response.

My compiler error is: "error: expected '{' before ';' token"
Haven't been able to satisfy it.

Any guidance appreciated.

[jlb]

You can't use the assignment operator= to assign one string to another, you will need to either use C++ strings or strcpy() if you want to stick with horrible C-strings.

[H00G0]

You could either overload the = operator or create a small quick function that replaces each char in the first array with the chars from the second one

[keskiverto]

You can't use the assignment operator= to assign one string to another

You can't use the assignment operator= to assign one plain array to another.
For the language an array is an array, char or not. All arrays fail the same.

A constant C-string literal, like "R2D2" is a shorthand for literal array { 'R', '2', 'D', '2', '\0' }.

You could either overload the = operator

No. Not for plain array. For user types, yes, but there is already "user type" std::string.

create a small quick function

Recreate strcpy() or other C-string handling functions from Standard C Library?
Reinventing a wheel is good for learning, but one should learn to use the existing wheels too.


Note that there is no "operator=" in the OP's code. The = is not that =.
What it is, is part of initialization syntax. Not an operator.

[H00G0]

Recreate strcpy() or other C-string handling functions from Standard C Library?
Reinventing a wheel is good for learning, but one should learn to use the existing wheels too.

Oh yes sure, but since strcpy() was mentioned by jlb I didn't emphasize on that further.

My bad on the operator part, thanks for making it clear!