2 numbers in one function
How do you return 2 numbers in one function? Thanks for answering.
#include <iostream>
using namespace std;
int swap(int &, int &);
int main () {
int a, b;
cout << "Please input 2 numbers" << endl;
cin >> a >> b;
cout << "The 2 numbers swapped are " << swap(a, b) << endl;
return 0;
}
int swap(int &x, int &y) {
int t = x;
x = y;
y = t;
return x;
return y;
}
#include <iostream>
using namespace std;
int swap(int &, int &);
int main () {
int a, b;
cout << "Please input 2 numbers" << endl;
cin >> a >> b;
cout << "The 2 numbers swapped are " << swap(a, b) << endl;
return 0;
}
int swap(int &x, int &y) {
int t = x;
x = y;
y = t;
return x;
return y;
}
You can return them through the function parameters, provided you make these references (as you have done, correctly).
Since nothing else needs to be returned, declare and define a void function:
and remove the lines
(because they are being returned through the function parameters, not the return value of the call).
PLEASE USE CODE TAGS
Since nothing else needs to be returned, declare and define a void function:
void swap(int &x, int &y)and remove the lines
|
|
(because they are being returned through the function parameters, not the return value of the call).
PLEASE USE CODE TAGS
Look at http://www.cplusplus.com/reference/algorithm/swap/
How does it "return" values?
A function can return at most one object. The object could be a primitive type or a class/struct. The latter can have multiple member variables.
How does it "return" values?
A function can return at most one object. The object could be a primitive type or a class/struct. The latter can have multiple member variables.
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