How do I accept multiple numbers

Sep 22, 2018 at 5:04am
closed account (9G3v5Di1)
Write a program that will accept a short value from 10 to 99 and display them per digit (separated by a space).

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#include <iostream>
#include "_pause.h"

using namespace std;

int main(){
	int num;

	cout << "Enter a number from 10 to 99: ";
	cin >> num;

	if(num > 9 && num < 100){
		cout << num;
	}

	cout << endl;
	
	std::cin.get();
	_pause();
	return EXIT_SUCCESS;
}


How do I accept multiple numbers?
Sep 22, 2018 at 5:26am
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if( num > 9 && num < 100 ) { // if it is a positive two digit number

    std::cout << num/10 /* first digit eg. 78/10 == 7 */ << ' ' /* space */ 
              << num%10 /* second digit eg. 78%10 == 8 */ << '\n' /* new line */ ;
}
Sep 22, 2018 at 5:44am
closed account (9G3v5Di1)
wow thank you
Sep 22, 2018 at 5:47am
closed account (9G3v5Di1)
what if I use two functions to do this.. is it possible? Because the problem came from the topic of 'Functions Procedures'
Sep 22, 2018 at 6:12am
It is possible. Try to do it.
Sep 22, 2018 at 6:42am
closed account (9G3v5Di1)
I've done it. Thank you!
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