inline functions

[trumpler]

I don't really understand inline functions.what inline does is that it replaces the called function with the code inside the function.so why doesn't this work?

  #include <iostream>
#include <string>
using namespace std;
void bob(int a,int b)
{
     a+b;

}
int main()
{
    int x;
x = inline bob(1,2);
cout<<x;

       //cout<<f;//bob(1,2);
}

[Repeater]

inline goes on the function declaration, not where you use it.

 #include <iostream>
#include <string>
using namespace std;
inline void bob(int a,int b)
{
     a+b;

}
int main()
{
    int x;
x =  bob(1,2);
cout<<x;

       //cout<<f;//bob(1,2);
}

Also, your function bob returns void. It doesn't return anything. So how are you expecting this to work:
x = bob(1,2);
given that the function bob doesn't return a value?