PAV CALCULATOR (P=PERIMETER, A= AREA, V= VOLUME)

[Mc Daniel]

Good day
I have a challenge in making my program to repeat its process

#include <iostream>
#include <cmath>
using namespace std;

int main()
{ float PI=3.1415926535;
int x;

cout <<"*******PAV CALCULATOR*******"<<endl;


cout <<"\nSELECT SCOPE OF FOCUS"<<endl;


cout <<"1.Volume\n2.Area\n3.Perimeter"<<endl;
cin >>x;

/** char again = 'y';
while ( again == 'y')**/
switch(x)
{
case 1:
int c;

cout << "CALCULATE VOLUME OF THE FOLLOWING SHAPES" << endl;
cout <<"\nVolume"<<endl;
cout <<"select a shape"<<endl;
cout <<"\n1.Sphere\n 2.Cone\n 3.Pyramid"<<endl;
cin >>c;


switch (c)
{
case 1:
float r,b;

cout << "CALCULATE VOLUME OF THE SPHERE" << endl;
cout <<"Sphere"<<endl;
cout <<"Enter radius"<<endl;
cin >>r; // r = radius

b=(((4/3)*(PI))*pow(r,3));
cout <<"The volume is = "<<b<<endl;
break;

case 2:
float a,d,e;

cout << "CALCULATE VOLUME OF A CONE\n" << endl;
cout <<"Cone"<<endl;
cout <<"Enter radius"<<endl;
cin >>a; //r= radius

cout <<"Enter height"<<endl;
cin >>d; //d= height

e=((PI*pow(c,2))*(d/3));
cout <<"The volume is = "<<e<<endl;
break;

case 3:
float f,g,h,i;

cout << "CALCULATE VOLUME OF A PYRAMID" << endl;
cout <<"Pyramid"<<endl;
cout <<"Enter length"<<endl;
cin >>f; // f= length of the pyramid

cout <<"Enter width"<<endl;
cin >>g; //g= width of the pyramid

cout <<"Enter height"<<endl;
cin >>h; //h= height of the pyramid

i=((f*g*h)/3);
cout <<"The volume is = "<<i<<endl;
break;
}

break;

case 2:
int f;
cout << "CALCULATE AREA OF THE FOLLOWING SHAPES" << endl;
cout <<"\nArea"<<endl;
cout <<"SELECT SHAPE\n"<<endl;
cout <<"\n1.Parallelogram\n2.Triangle\n3.Trapezoid\n4.Circle\n5.Ellipse\n6.Sphere\n7.Cylinder"<<endl;
cin >>f;
switch (f)
{
case 1:
int a,b,c;
cout << "CALCULATE AREA OF A PARALLELOGRAM" << endl;

cout <<"Parallelogram"<<endl;
cout <<"Enter the height"<<endl;
cin >>a; // a= the height of a parallelogram

cout <<"Enter the width"<<endl;
cin >>b; // b= width of a parallelogram

c=a*b;
cout <<"The area is = "<<c<<endl;
break;

case 2:
int d,e,f;

cout << "CALCULATE AREA OF A TRIANGLE" << endl;

cout <<"Triangle"<<endl;
cout <<"\nEnter the height"<<endl;
cin >>d; // d= the height of a triangle

cout <<"Enter the width"<<endl;
cin >>e; // e= the width of a triangle

f=0.5*(e*d);
cout <<"The area is = "<<f<<endl;
break;

case 3:
int g,h,i,j;

cout << "CALCULATE AREA OF A TRAPEZOID" << endl;

cout <<"Trapezoid"<<endl;
cout <<"\nEnter first length"<<endl;
cin >>g; //f= the first length of a trapezoid

cout <<"Enter second length"<<endl;
cin >>h; // h= the second length of a trapezoid

cout <<"Enter the height"<<endl;
cin >>i; // i= the height of a trapezoid

j=((h+g)/2)*i;
cout <<"The area is = "<<j<<endl;
break;

case 4:
float k,l;

cout << "CALCULATE AREA OFA CIRCLE" << endl;

cout <<"Circle"<<endl;
cout <<"\nEnter the radius"<<endl;
cin >>k; // k= radius of a circle

l=PI*pow(k,2);
cout <<"The area is = "<<l<<endl;
break;

case 5:
float m,n,o;
cout <<"Ellipse"<<endl;
cout <<"\nEnter the height"<<endl;
cin >>m;

cout <<"Enter the width"<<endl;
cin >>n;

o=PI*m*n;
cout<<"The area is = "<<o<<endl;
break;

case 6:
float p,q;

cout << "CALCULATE SURFACE AREA OF A SPHERE" << endl;
cout <<"Sphere"<<endl;
cout <<"\nEnter the radius"<<endl;
cin >>p; // p= radius of a sphere

q=4*PI*pow(p,2);
cout <<"The surface area is = "<<q<<endl;
break;

case 7:
float r,s,t;

cout << "CALCULATE SURFACE AREA OF A CYLINDER" << endl;

cout <<"Cylinder"<<endl;
cout <<"\nEnter radius"<<endl;
cin >>r; //r= radius of a cylinder

cout <<"Enter height"<<endl;
cin >>s; // s= height of a cylinder

t=(2*PI*r*s)+(2*PI*pow(r,2));
cout <<"the whole surface area is = "<<t<<endl;
break;
}
break;


case 3:
int d;
cout << "CALCULATE PERIMETER OF LISTED SHAPES" << endl;

cout <<"\nPerimeter"<<endl;
cout <<"SELECT SHAPE TO CALCULATE"<<endl;
cout <<"1.Rectangle\n2.Parallelogram\n3.Trapezoid\n4.Circle\n5.Ellipse"<<endl;
cin >>d;
switch (d)
{

case 1:
int length,width,perimeter;
cout << "CALCULATE PERIMETER OF A RECTANGLE" << endl;
cout <<"Rectangle"<<endl;
cout <<"\nEnter Length"<<endl;
cin >>length;

cout <<"Enter width"<<endl;
cin >>width;

perimeter=2*(length+width);
cout <<"The perimeter is = "<<perimeter<<endl;

break;

case 2:
int a,b,c;

cout << "CALCULATE PERIMETER OF A PARALLELOGRAM" << endl;
cout <<"Parallelogram"<<endl;
cout <<"\nEnter Length"<<endl;
cin >>a; // a= the length of a parallelogram

cout <<"Enter width"<<endl;
cin >>b; // b= the width of a parallelogram

c=2*(a+b);
cout <<"The perimeter is = "<<c<<endl;

break;

case 3:
int l1,l2,w1,w2,d;

cout << "CALCULATE PERIMETER OF A TRAPEZOID" << endl;

cout<<"Trapezoid"<<endl;
cout<<"\nEnter Length1"<<endl;
cin>>l1; //l1= the first length of the trapezoid

cout<<"\nEnter Length2"<<endl;
cin>>l2; // l2= the second length of the trapezoid

cout <<"Enter width1"<<endl;
cin >>w1; // w1= the first width of the trapezoid

cout <<"Enter width2"<<endl;
cin >>w2; // w2= second width of the trapezoid

d=(l1 + l2 + w1 + w2);
cout <<"The perimeter is = "<<d<<endl;
break;

case 4:
float radius,e;

cout << "CALCULATE PERIMETER OF A CIRCLE" << endl;

cout <<"Circle"<<endl;
cout <<"\nEnter radius"<<endl;
cin >>radius;

e=2* PI*radius;

cout <<"The perimeter is = "<<e<<endl;
cout <<"Circle"<<endl;
break;

case 5:
{
int h,i,j;

cout << "CALCULATE PERIMETER OF AN ELLIPSE" << endl;

cout <<"Ellipse"<<endl;
cout <<"\nEnter Length"<<endl;
cin >>h; // h= length of an ellipse

cout <<"Enter width"<<endl;
cin >>i; // i= width of an ellipse

j=2*(h+i);
cout<<"The perimeter is = "<<j<<endl;
break;

default: cout <<("\n Invalid choice")<<endl;


}




}
// cin >>again;

}
return 0;
}

[Repeater]

char repeat = 'y';
while (repeat == 'y')
{
  /// PUT ALL THE CODE YOU WANT TO BE REPEATED HERE

  cout << "Repeat (enter y to repeat)?";
  cin >> repeat;
}

[Mc Daniel]

Thank you, now my program is good

[Mc Daniel]

i need a little help again, i want to insert a termination option in my menu, so that the user can terminate if her/she want

[jonnin]

add a case for an exit code, and change the loop logic to end if the user input is that code. Its very like what you have already.