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Double variables being truncated

Brandon110 (3)
Hello I am new to the programming community. I'm writing a code to calculate gym fees over years and I'm experimenting with loops.
I have come across an issue where my double variables are being "truncated" (I believe its called from research) and i don't know why. Everything seems to work how i want it to so far (I'm not completely done finishing the quit option) except the variables are converting to integers when I use cout. I've done a lot of google research and reading but can't seem to pinpoint it. If someone could help me understand the problem, if I'm just making a silly mistake.
I am working in Microsoft Visual Studio Basic 2017.
Like I said I'm not completely done but i ran into this issue and I really want to understand why it is happening and how to fix it. Thank you so much.

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#include "stdafx.h"
#include <iostream>
#include <iomanip>
using namespace std;


int main()
{
	//A) Declare necessary variables for user input and calculations

	int userInput, counter;
	const double GOLD = 0.01,
				SILVER = 0.02,
				BRONZE = 0.04,
				INITIAL_FEE = 1200.00;
	double yearlyFee, tempVal, feeVal;

	//B) Display menu

	cout << "	Welcome to Ronda's Strikeforce Gym!!\n";
	cout << "x--------------------------------------------------- x\n";
	cout << "	   Membership Fee Calculator\n\n";
	cout << "	1. Gold\n";
	cout << "	2. Silver\n";
	cout << "	3. Bronze\n";
	cout << "	4. Quit\n\n";
	cout << "Please enter your membership level(1 - 3, or 4 to quit) : ";

	//C) Read in the input from the user

	cin >> userInput;

	//D) Validate user input(must input 1 through 4), loop if value is invalid

	while (userInput < 1 || userInput > 4)
	{
		cout << "\nError. Please enter a valid menu choice (1-4):";
		cin >> userInput;
	}

	//E) If values 1 - 3 were entered perform calculations else if 4 was entered exit program with thank you message.

	if (userInput == 1) feeVal = GOLD;
	else if (userInput == 2) feeVal = SILVER;
	else if (userInput == 3) feeVal = BRONZE;
	else if (userInput == 4) cout << "Thank you for using Rhonda's Fee Calculator!";
	
	//E.1) Perform calculation for specified membership for 10 years and output. (This will require a loop.)
	
	yearlyFee = INITIAL_FEE;

	for (counter = 1; counter <= 10; counter++)
	{	
		
		tempVal = INITIAL_FEE * feeVal;
		yearlyFee += tempVal;

		cout << fixed << showpoint << setprecision(2);
		cout << "\nYear\t" << counter << "\t" << "$" << yearlyFee;
	}

	

	cout << endl << endl;

    return 0;
}



Welcome to Ronda's Strikeforce Gym!!
x--------------------------------------------------- x
Membership Fee Calculator

1. Gold
2. Silver
3. Bronze
4. Quit

Please enter your membership level(1 - 3, or 4 to quit) : 1

Year 1 $1212.00
Year 2 $1224.00
Year 3 $1236.00
Year 4 $1248.00
Year 5 $1260.00
Year 6 $1272.00
Year 7 $1284.00
Year 8 $1296.00
Year 9 $1308.00
Year 10 $1320.00

Press any key to continue . . .
Last edited on
Marcus Aseth (113)
Your numbers are not being truncated, just regular math I guess.

Try an INITIAL_FEE = 1200.78; you'll get decimals.
Brandon110 (3)
Thank you, when i do that decimals do show up. But when you do this very basic math on calculator you get different answers. Ex: Year 2 should be 1224.12. Is there a way to get these decimals without putting .78? Shouldn't it already be showing up?
Peter87 (11238)
I think you might want to multiply with yearlyFee instead of INITIAL_FEE when calculating the fee increase on line 55.
Brandon110 (3)
I knew it was a stupid mistake of mine lol. It works now thank you
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