Function accepting arguments of objects with 2 arrays

[drew026]

Hello again! I've almost figured this out, but I'm confused on how to pass some arguments to my function. Below I have a function multiplyArrays(Time). It accepts an object Time, that has 2 arrays in it, x[] and y[]. Each has already been initialized with 10,000 doubles. I want the function to multiply x and y for each of the 10,000 entries.

However, I'm lost on how to pass that information to my function. I've tried a few different things, but my head is pounding now... and I'm taking a break from it. Any help would be appreciated! I put the code below, I expect I am missing some statements in the function to assign to the arrays... but I'm not sure. I left out my constructor for the class Time.

void multiplyArrays(Time) {			// Multiply 2 arrays	
	for(int i = 0; i < 10000; i++) {	// For loop to run 10,000 times
		cout << x[i] << " * " << Time::y[i] << " = " << (x[i]*y[i]) << "\n";	// Display the results of the multiplication
	}

int main() 
{
	Time myArrays;		// Create and initialize an object myArrays, calls constructor.
	
	multiplyArrays(myArrays);		// Call the function to multiply the arrays in myArrays. 

[Ganado]

You would pass it in the same way you pass in any other variable.

How would you pass in an int to a function?

void my_func(int a)
{
    cout << a << endl;
}

The name of the int is a in the above example.
But you never gave an actual name to your Time object.

You could make the definition of the function something like:
void multiplyArrays(Time time) { ... };

However, copying two large arrays is expensive, so I would suggest passing by a constant reference instead. Your full definition and implementation would look like this:

void multiplyArrays(const Time& time) {
	for (int i = 0; i < 10000; i++) {
		cout << time.x[i] << " * " << time.y[i] << " = " << (time.x[i]*time.y[i]) << "\n";
	}
}

If you're still having trouble, give the definition of your class. If your x and y arrays are static, then my way won't work.