Modulo operation with all elements of an array

[pcblockgermany]

Hello,

I'm new to C++ and wanted to write some code which adds all natural numbers from 0 to the number given by the user except those, that are divisible by one of the numbers in an array. Here is my code:

#include "stdafx.h"
#include <iostream>
#include <string>
#include <sstream>
#include <array>
using namespace std;

int main()
{
	int x{ 1 };
	int sum{ 0 };
	int divisors[] = { 3, 5 };
	string userInput = "";

	cout << "Please enter a natural number: ";
	getline(cin, userInput);
	stringstream(userInput) >> x;

	for (int i = 0; i <= x; i++)
	{
		if (!(i % divisors[1] == 0))
			sum += i;
	}

	cout << "\nThe sum is: " << sum << "\n";

	return 0;
}

Right now it's just checking if it's divisible by 3, but can I make it do the modulo operation with all elements of the array without having to loop through it?

Thanks in advance!

[keskiverto]

You are testing divisibility by 5, for index 1 is the second element in an array. First element has index 0.

Yes, you need to loop somehow. For example:
http://www.cplusplus.com/reference/algorithm/none_of/