Expression and statement confusion
Hi,everyone. I am confused with the questions below. Can someone help me?
Which of these statements are true?
(a) Any expression can be used as a statement in C++.
(b) The expression x++ can be used as a statement.
(c) The statement x = x + 5 is also an expression.
(d) The statement x = y = x = 0 is illegal.
Which of these statements are true?
(a) Any expression can be used as a statement in C++.
(b) The expression x++ can be used as a statement.
(c) The statement x = x + 5 is also an expression.
(d) The statement x = y = x = 0 is illegal.
> (a) Any expression can be used as a statement in C++.
Yes, as an expression statement with a semicolon at its end; (the expression is a discarded value expression).
> (b) The expression x++ can be used as a statement.
> (c) The statement x = x + 5 is also an expression.
x++ is an expression and x++; is a statement (an expression statement, note the semicolon).
x = x + 5; appearing by itself is a full statement terminated by a semicolon, it is not an expression.
x = x + 5 is an expression
> (d) The statement x = y = x = 0 is illegal.
To make it a syntactically valid statement, add a semicolon at the end x = y = x = 0;
Note:
If x is an object of a scalar type, evaluating x = y = x = 0 engenders undefined behaviour prior to C++17.
Yes, as an expression statement with a semicolon at its end; (the expression is a discarded value expression).
> (b) The expression x++ can be used as a statement.
> (c) The statement x = x + 5 is also an expression.
x++ is an expression and x++; is a statement (an expression statement, note the semicolon).
x = x + 5; appearing by itself is a full statement terminated by a semicolon, it is not an expression.
x = x + 5 is an expression
> (d) The statement x = y = x = 0 is illegal.
To make it a syntactically valid statement, add a semicolon at the end x = y = x = 0;
Note:
If x is an object of a scalar type, evaluating x = y = x = 0 engenders undefined behaviour prior to C++17.
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