pointers with bank account

[yoyotheyogurt]

i'm having trouble figuring how to make a pointer to my main function from my account class and my derived checking account class and savings account class.
this is what i got. it doesnt have the savingsccount in there yet. but i'm trying to make it so theres a constructor that has my derived classes of checkingaccount and savingsaccount i get this error
error C3867: 'CheckingAccount::doDebit': non-standard syntax; use '&' to create a pointer to member

  int main()
{
	Account * accounts;
	accounts = new Account[2];
	CheckingAccount c;
	accounts[0] = & c;

[keskiverto]

Your accounts is a pointer. The pointer points to first element of an array that has two Account objects (line 4).

Your c is a CheckingAccount object. On line 6 you try to take the address of that object and store the address into an object.

Does this look sane?

double foo = 3.14;
int * pbar;
foo = pbar;

It should not.


This would not stop on syntax error:

int main()
{
  CheckingAccount c;
  SavingAccount s;
  Account* accounts[] = { &c, &s };

Logical sanity ... not guaranteed.


Oh, your error message has nothing to do with the code that you show. That error is elsewhere.

[gunnerfunner]

since SavingsAccount and CheckingAccount are derived from Account consider using base class pointers to access derived classes as well - a simple example:

# include <iostream>
# include <vector>
# include <memory>

struct Account
{
    virtual void id()const {std::cout << "account \n";}
};
struct CheckingAccount : public Account
{
    void id()const final {std::cout << "checking account \n";}
};
struct SavingsAccount : public Account
{
    void id()const final { std::cout << "savings account \n";}
};

int main()
{
    std::vector<std::unique_ptr<Account>> my_accounts{};

    my_accounts.emplace_back(std::make_unique<Account>());
    my_accounts.emplace_back(std::make_unique<CheckingAccount>());
    my_accounts.emplace_back(std::make_unique<SavingsAccount>());

    for (const auto& elem : my_accounts) elem -> id();
}