Need help with this program! plzzzzz

[WhiteTiger]

// Program to accept integers from the keyboard until a zero is entered. Print the sum and average of the even numbers. Ignore any odd numbers in your calculations and print an appropriate message.

#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

void pause ()
{
string junk;
cout << "Press enter to continue... ";
cin.ignore();
getline(cin, junk);
}

int main()
{
// Declare variables and constants
int total;
int number;
int average;

// Calculate
total=0;
number=1;
bool done=(number=0);

while (!done)
{
cout << "Enter whole numbers until average is provided: ";
cin >> number;}

if (number%2)
{
done =(number=0);
total=total +number;
average=total/number;
}
// Display results
else {}{
cout << "The sum of the positive even numbers is " << total << endl;
cout << "The average of positive even number is " << average << endl;

pause();
}
return 0;
}

[JLBorges]

#include <iostream>        
    
int main()
{
    std::cout << "enter whole numbers one by one. enter zero to end input\n" ;
    
    int cnt = 0 ; // count of even numbers
    int sum = 0 ; // sum of even numbers
    int number ;
    
    // for as long as a number is entered and the number is not zero
    while( std::cin >> number && number != 0 )
    {
        if( number%2 == 0 ) // if the number is even
        {
            ++cnt ; // increment count
            sum += number ; // add to sum
        }
    }

    if( cnt > 0 ) // if there was at least one even number
    {
        std::cout << "sum of even numbers: " << sum << '\n' ;
        const double average = double(sum) / cnt ;  // avoid integer division
        std::cout << "average of even numbers: " << average << '\n' ;
    }

    else std::cout << "there were no even numbers in the input\n" ;
}

[eec]

that is simple:

#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

void pause ()
{
	string junk;
	cout << "Press enter to continue... ";
	cin.ignore();
	getline(cin, junk);
}

int main(int argc, char ** argv)
{
	///variables
	int total=0;
	int number;
	bool done = 0;
	float average;///must use float, to hold float result on it
	int N = 0 ;/// # of number intered

	while (1){
		
		cout << "Enter whole numbers until average is provided: ";
		cin >> number;
		
		if (number == 0){
			cout<<"0 entered\n";
			break;/// goto after while
		}
		
		if (!(number % 2)){ /// intered number is even 
			N++;
			total = total + number;
			average = (float) total / N;
			
		}else {///odd
			;/// do nothings
		}
		cout<<"N:"<<N<<endl;
	}

	cout <<"after While\n";


	// Display results
	cout << "The sum of the even numbers is " << total << endl;
	cout << "The average of even number is " << average << endl;

	pause();

	return 0;
}

ss@ss:~$ g++ ttt.cpp -o ttt
ss@ss:~$ ./ttt
Enter whole numbers until average is provided: 10
N:1
Enter whole numbers until average is provided: 20
N:2
Enter whole numbers until average is provided: 30
N:3
Enter whole numbers until average is provided: 0
0 entered
after While
The sum of the positive even numbers is 60
The average of positive even number is 20
Press enter to continue... 

this is only care about even not positive even.
if you wish change code to be sensitive about positive numbers, simply add a condition in
if /// even section.