Storing std/boost::arrays in a vector

[zoran404]

Since I assume this wont make a deep copy of the array (but instead just copy the pointer) I was wondering what is the proper way to store a copy of std or boost array.

void AddAnother(array<uint32_t,4> &temporaryArray)
{
	myVector.push_back(temporaryArray);
}

[JLBorges]

> I assume this wont make a deep copy of the array (but instead just copy the pointer)

std::array<> has value semantics, a copy of the array would be made.

#include <iostream>
#include <array>

int main()
{
    const std::array<int,25> a {} ;
    auto cpy = a ;

    std::cout << std::boolalpha << (a==cpy) << '\n' // true
              << ( a.begin() == cpy.begin() ) << '\n' ; // false

    cpy[4] = 78 ; // the copy is modified
    std::cout << (a==cpy) << '\n' ; // false
}

[gunnerfunner]

The data() member method of std::array

(r)eturns pointer to the underlying array serving as element storage

http://en.cppreference.com/w/cpp/container/array/data
so, for example:

std::vector<uint32_t*> AddAnother(std::array<uint32_t,4> &temporaryArray)
{
	std::vector<uint32_t*> myVec{};
	myVec.push_back(temporaryArray.data());
	return myVec;
}

[zoran404]

@JLBorges Great so the a duplicate would be stored in the vector. Looks like I assumed wrong. Thanks!


@gunnerfunner I think you misunderstood my problem, the temporary array will be destroyed right after calling this function. So there is no point in storing the data pointer.