split vs conjoined operators

[propogrationdragon]

So I'm looking at what I *think* is a typo in my textbook and a half hour on Google can't give me a solid yes/no either way.

We're looking at operators that combination some arithmetic operation and set the assignment and using the same language to test boolean values. i.e. a = a + b :: a += b

My question is do compilers treat all spaces as delimiters and have a break or pause in the logic unit? I'm looking at as follows:

r > = 4;

Can the compiler discern we're meaning >= or are spaces in the middle of combo-operators allowed?

[cire]

Can the compiler discern we're meaning >= or are spaces in the middle of combo-operators allowed?

If spaces are not allowed, your code is equivalent to: (r > =) 4; which won't compile.

If spaces are allowed, your code is equivalent to: (r >= 4); which will compile.

So, if it compiles, spaces are allowed and ff it doesn't, spaces are not. Have you tried to compile it?

[propogrationdragon]

Honestly, no. But it's one of 20 or so statements in the book we're supposed to say work or don't.

[keskiverto]

A First Book of C++ by Gary J. Bronson apparently describes tokens on its page 15:
https://books.google.com/books?id=2dgIAAAAQBAJ&pg=PA15&lpg=PA15&dq=C%2B%2B+multi-character+tokens&source=bl&ots=KlzNtzexMa&sig=stWV_X9hHtKCBuTlCMiNWFhCkvc&hl=fi&sa=X&redir_esc=y#v=onepage&q=C%2B%2B%20multi-character%20tokens&f=false

The greater-or-equal is a token. It is a multicharacter token.

[propogrationdragon]

@keskiverto
Thank you! Never heard operators clled tokens, but it makes sense.