seemingly simple expression yields embarrassing result. Help!

[davBams]

Write your question here.
pls can anybody help me with why (212-32)/100 as shown below yield 1 instead of 1.8.

  float nfactor;
  nfactor = (212-32)/(100);

[AbstractionAnon]

You're doing integer division. The result is converted to a float only when the assignment is done. Try this instead:

  nfactor = (212-32)/(100.0);  // Note the decimal place which makes the divisor a double 

[Naughty Albatross]

Hi,
You should write your expression like this :
(212.0-32.0)/100.0

[Naughty Albatross]

Because if they are integers, there are quotient & remainder. But if they are double (eg: 212.0), none of these things matters anymore.

[Naughty Albatross]

And you also use a double variable to retrieve the result of the expression, like this :
double a = (212.0-32.0)/(100.0);

[Naughty Albatross]

Does that help? :)

[davBams]

Thanks a lot. it skipped my mind... a times u just forget those small things...