Help with program that will print integer digits in reverse with spaces in between

[ozTkSL3A]

Hey guys, I'm currently stuck with trying to have spaces in between the digits of my output. What I have currently will not place the spaces in between the digits. For example, if the input was 12345, the output should be 5 4 3 2 1. Also, I have to use a while loop and have not yet reached arrays yet. Thanks guys!

#include <iostream>
using namespace std;

int main() {
	int n, reverse = 0;

	cout << "Enter an integer: ";
	cin >> n;
	while (n != 0) {
		int remainder = n % 10;
		reverse = reverse * 10 + remainder;
		n /= 10;
	}

	cout << "Reversed number = " << reverse;

	return 0;
}

[Naughty Albatross]

Hi,

Try this :

#include <iostream>

using namespace std;
int main() 
 {
	int n;
	cout << "Enter an integer: ";
	cin >> n;

	cout << "Reversed number = ";
 	if(n < 0) cout << "- ";
	do
     {
		int remainder = n % 10;
		cout << remainder << ' ';
		n /= 10;
	}while (n != 0);
 	return 0;
 }

[Naughty Albatross]

Does that help you? : )

[JLBorges]

#include <iostream>

int main() {

    int n ;
    std::cout << "Enter an integer: ";
    std::cin >> n ;

    std::cout << "\nnumber: " << n << "\nreversed number with spaces in between: " ;

    if( n < 0 ) { // take care of negative numbers

        std::cout << "- " ; // print a leading negative sign
        n = -n ; // and then ignore the negative sign
    }


    do { // change while to do-while to make sure the loop executes at least once
         // (if the number is zero, one zero must be printed).

        std::cout << n % 10 << ' ' ; // print a space after each digit
        n /= 10 ;

    } while( n != 0 ) ;

    std::cout << '\n' ;
}

http://coliru.stacked-crooked.com/a/f450548ea66b66ea

[ozTkSL3A]

Thanks guys for the responses. I got it!
You guys are awesome.