How to get the sum of the columns in the array

[travina8]

For the program I had to pull the information for the first 4 columns from a file called BusInput.txt with this in it.
111 100.00 200.00 50.00
222 200.00 300.00 100.00
333 400.00 500.00 75.00

The last 2 columns I calculated with a variable.
NOW, I need to find the sum of all of the columns EXCEPT the Bus No.

This is my current code. How do I get the sum of all of the columns?

#include <iostream>
#include <iomanip>
#include <fstream>

const int ROW = 200;
const int  COL = 6;
int total = 0;
int count = 0;
int num[ROW][COL];
int next, busNum;
double fuel, equip, misc, dFuel, finCost;

using namespace std;

int main()
{
	ifstream inputFile;
	ofstream outputFile;

	//system("color 0a");
	cout << "Tour Bus Company \n\n";
	
	cout << left << fixed << setprecision(2);
	cout << setw(12) << "Bus No." << setw(10) << "Fuel" << setw(15);
	cout << "Equipment" << setw(10) << "Misc" << setw(20);
	cout << "Discount Fuel" << setw(15) << "Final Cost" << endl;

	inputFile.open("BusInput.txt");
	if (!inputFile)
	{
		cout << "Error opening file";
		return -1;
	}
	 
	while (inputFile >> busNum >> fuel >> equip >> misc) 

	{	
		dFuel = fuel * 0.9;
		finCost = dFuel + equip + misc;

		cout << right << fixed << setprecision(2);
		cout << setw(7) << busNum << setw(9) << fuel << setw(15);
		cout << equip << setw(10) << misc << setw(19);
		cout << dFuel << setw(17) << finCost << endl;
		
	}
	for (int col = 0; col < COL; col++)
	
	
				for (int row = 0; row < ROW; row++)
					total += num[row][col];
		
		cout << "Totals " << total << endl;
		

	cin.ignore(1); // used to pause the system instead of system("pause")
	//system("pause");
	return 0;

}
 

[Briez]

How about starting your "for" with col = 1?
It skips adding the bus numbers to the sum.

[keskiverto]

What if the input had just "one column" and you would need the sum of the values? You can do that without an array. Same principle applies here.

[travina8]

I need it to be an array. Also, my problem is I can not get any of the columns to output a sum. My only output is one 0 under the first column.

[keskiverto]

You don't read anything into the array 'num'. Then you nevertheless sum up all the (undefined) values of the array to one variable: 'total'.

When you do:
cout << "Totals " << total << endl;
you do print exactly one value.


You cannot have a 2D array of all the input values, because the first column is int and the rest are double.
You could have 1D array of struct type that has four members: busNum, fuel, equip, misc

Why do you need an array?

double sFuel = 0.0;
while (inputFile >> busNum >> fuel >> equip >> misc ) {
  sFuel += fuel;
}
std::cout << sFuel << '\n';

See? No array. Sum of specific column.

[travina8]

keskiverto,

I don't need the sum of the first column so maybe that is why the professor set it up that way?
I have actually already done the program with variables set up just like sFuel += fuel; so that I could finish the rest of it.
The array is part of the assignment or I would have just left it with the variables which work without issue. I found the code with the for loops online on several sites as well as in my book. I was unable to make it work that's when I turned to this forum.
I figured it must be an issue somewhere in my code preventing it.

[keskiverto]

If you do have to have an array:

double sFuel = 0.0;
size_t rows = 0;
while ( inputFile >> busNum >> fuel >> equip >> misc && rows < ROW ) {
  num[ rows ][ 1 ] = fuel;
  num[ rows ][ 2 ] = equip;

  sFuel += num[ rows ][ 1 ];
  ++rows;
}
std::cout << sFuel << '\n';

Or in separate stages:

size_t rows = 0;
while ( inputFile >> busNum >> fuel >> equip >> misc && rows < ROW ) {
  num[ rows ][ 1 ] = fuel;
  num[ rows ][ 2 ] = equip;
  ++rows;
}

double sFuel = 0.0;
for ( size_t row = 0; row < rows; ++row ) {
  sFuel += num[ row ][ 1 ];
}
std::cout << sFuel << '\n';

[travina8]

Thank you! I will get to work on that right now!