Using variables created in function into the main

[BlueOctopus]

Hello. My question is rather stupid but anyway: What are the ways so the main has access to the variable created in a function and vice-versa? Here the problem is of course that the variable "s" has not been declared.

#include <iostream>
using namespace std;

void add();

int main(){
    
    add();
    cout<<s<<endl;
    
    
}


void add(){
    float a;
    float b;
    float s;  //sum
    
    cin>>a;
    cin>>b;
    
    s = a + b ;
  
}

Sorry for the probably stupid question but I don't have a professor so I will annoy you. Thank you in advance.

[TarikNeaj]

Your solution would be simply to make the function return it.

#include <iostream>
using namespace std;

float add();

int main(){
    
   float s =  add();
    cout<<s<<endl;
    
    
}


float add(){ 
    float a;
    float b;
    float s;  //sum
    
    cin>>a;
    cin>>b;
    
    s = a + b ;
    return s;
  
}

Edit: Corrected my mistake, thank you @AbstractionAnon.

[AbstractionAnon]

@TarikNeaj - Line 7: You need to declare s within main.

  float s;

[BlueOctopus]

Thank you guys very much. The tutorials that I was watching never mentioned what the return does. So what it does if I understood correctly is saying that the value "s" can be used and into the main. Right?

[BlueOctopus]

OK. Just read the article that you have in this site and now everything is clear. Thank you

[BlueOctopus]

Another relevant question. If I want to return more than 1 values can I just write many times "return x;"?

[Moschops]

Another relevant question. If I want to return more than 1 values can I just write many times "return x;"?

No.

If you want to return many values, pass them in by reference, or pass in pointers to them, or return some kind of composite variable containing many sub-variables (like a struct), or return a container of variables.