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Not sure how to go about outputing the occurance of an integer in an array

willmannix1 (12)
Basically for a college assignment I have to create a menu by creating an array and outputting to the screen a number of options which the user can pick such as

press 1 for the smallest number in the array
press 2 for largest number
press 3 for the average number in the array
etc

using a switch statement

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 int big, small, maxCount = 0;
	int list[12];
	int option;
	int sum = 0;
	big = small = list[0];

	cout << "Enter 12 numbers : ";
	for (int i = 0; i < 12; i++)
	{

		cin >> list[i];

	}

	do
	{

		cout << "\t\tMenu\n";
		cout << "\t0.Display\n";
		cout << "\t1.Total\n";
		cout << "\t2.Average\n";
		cout << "\t3.Largest\n";
		cout << "\t4.Smallest\n";
		cout << "\t5.Occurance of value\n";
		cout << "\t99.Exit\n";
		cout << "\t\t Option ? ";
		cin >> option;


		switch (option)
		{
		case 0:

			cout << "Contents\n";


			for (int i = 0; i < 12; i++)
			{
				cout << list[i] << endl;

			}
			break;

		case 1:

			cout << "Total";
			cout << "\n\n";

			for (int i = 0; i < 12; i++)
			{


				sum += list[i];

			}

			cout << sum;

			break;

		case 2:

			cout << "average";

			for (int i = 0; i < 12; i++)
			{
				sum += list[i];

			}

			cout << setprecision(1) << fixed << sum / 12;

			break;

		case 3:

			cout << "Largest";

			for (int i = 0; i < 12; i++)
			{
				if (list[i] > big)
				{
					big = list[i];
				}

			}

			cout << big;

			break;

		case 4:

			cout << "Smallest";

			for (int i = 0; i < 12; i++)
			{
				if (list[i] < small)
				{
					small = list[i];
				}

			}

			cout << small;

			break;

		case 5:

			cout << "Occurances of value";

			for (int i = 0; i < 12; i++)
			{
				int count = 1;
				for (int j = i + 1; j < 12;j++)
			
					if (list[i] == list[j])
						count++;
			
				if (count > maxCount)
					maxCount = count;

				for (int i = 0; i<5; i++)
				{
					int count = 1;
					for (int j = i + 1; j<5; j++)
						if (list[i] == list[j])
							count++;
					if (count == maxCount)
						cout << list[i] << endl;
				}
			}

			break;


case 5 in the switch statement is the one i need help with, basically i need to enter a value and output to the screen the number of times it appears in the array but im not sure how to go about approaching it, i formulated that code in case 5 from another person online but i dont entirely understand it, Help would be much appreciated
AbstractionAnon (6954)
You're overly complicating it. 
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  int val;
  int cnt = 0;  
  cout << "Enter value to search for: ";
  cin >> val;
  for (int i=0; i<12; i++)
    if (list[i] == val)
        cnt++; 
  cout << val << " occurs " << cnt << " times" << endl;

Last edited on
willmannix1 (12)
thank you :)
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