return pointer of an array
I keep getting this error "[Error] invalid conversion from 'int*' to 'int' [-fpermissive]", I have tried everything and still cant fix the error. Any hints?
#include <iostream>
using namespace std;
int *arr_expander(int array, int size);
int main() {
int nums[]={2,3,4,6,7};
int size = 5;
int *expander= arr_expander(nums, size);
for(int i=0; i<size*2;i++){
cout<<expander[i];
}
system("PAUSE");
return 0;
}
int *arr_expander(int array[], int size){
int *p = new int[size*2];
for(int i =0; i<size*2;i++){
if (i<size)
p[i]=array[i];
else
p[i]=0;
}
return p;
}
#include <iostream>
using namespace std;
int *arr_expander(int array, int size);
int main() {
int nums[]={2,3,4,6,7};
int size = 5;
int *expander= arr_expander(nums, size);
for(int i=0; i<size*2;i++){
cout<<expander[i];
}
system("PAUSE");
return 0;
}
int *arr_expander(int array[], int size){
int *p = new int[size*2];
for(int i =0; i<size*2;i++){
if (i<size)
p[i]=array[i];
else
p[i]=0;
}
return p;
}
Sorry i still don't understand, dont I need to declare it as an int since the elements in the array are ints? Can you please elaborate a little further?
int *arr_expander(int array, int size);int *arr_expander(int array[], int size){See the difference? The first one is missing the [].
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