Reading the line below.

[Axarator]

I have created a program that you search all the users that have ever used the program, but you need to enter your details to search. It is all fine and not buggy, but I have one thing I would like to know how to do. I would like to know so that when it searches it will enter everything on the line the string was found and the line below.

 inFile.open("data.txt");
    cout << "\n";
    cin.get(entr); //dont worry about this. this is just something you don't need to know about.
    cout << "\nYou may now search a user\n";
    cout << "\nEnter a students first or last name ((Case sensitive))\n";
    getline (cin, search);
    cout << "\n Searching for " << search <<"\n";
	{
    size_t pos;
while(inFile.good())
  {
      getline(inFile,line); // get line from file
      pos=line.find(search); // search
      if(pos!=string::npos) // string::npos is returned if string is not found
        {
            cout << search << " Found!"; //this is where I want it to display the line the string was found and the line below, because the line below has the age.
            break;
        }
  }

[Axarator]

bump

[Peter87]

You can use a variable that you incremenent in the loop to keep track of which line you are at. Use getline to read the next line.

[Axarator]

I'm a bit of a noob, can you give me an example of how I could do this?