How would I be able to put these together?

[Blackhart98]

Instead of calling in two different pointers to new; how would I make an instance where I just need to call one in. Instead of creating sepreate u and p just call one pointer to get both of the virtual methods ,or is something like that takes up to much memory. Here's the code.

#include <iostream>

using namespace std;
class Thisthing
{
public:
    virtual void Eatsomething()
    {
        cout << "He is being eaten" << endl;
    }
private:
    int Dont_Eat_Him;
};
class Bringit : Thisthing
{
public:
     void Eatsomething()
     {
         cout << "He's going to be ate" << endl;
     }
};

int main()
{
    Thisthing *p = new Thisthing;
    Bringit *u = new Bringit;
    p->Eatsomething();
    u->Eatsomething();
}

[Blackhart98]

Also I am not new to polymorphism or dynamic memory by a long shot. I just wanted to know if I can do something where you only need one pointer to Thisthing and Bringit. This is the way it was taught to me ,but by my small expereince there is always a different way to do something.

[JLBorges]

#include <iostream>

class Thisthing
{
    public:
        virtual ~Thisthing() {} // = default ; // http://www.stroustrup.com/C++11FAQ.html#default

        virtual void Eatsomething() const // const
        {
            std::cout << "He is being eaten\n" ; // << endl;
        }
    private:
        // int Dont_Eat_Him = 0 ; // http://www.stroustrup.com/C++11FAQ.html#member-init
};

class Bringit : public Thisthing // note: public
{
    public:
        virtual void Eatsomething() const // override // http://www.stroustrup.com/C++11FAQ.html#override
        {
            std::cout << "He's going to be ate\n" ; // << endl;
        }
};

int main()
{
    Thisthing* pointer = 0 ; // = nullptr; // http://www.stroustrup.com/C++11FAQ.html#nullptr

    Bringit bring_it ;
    pointer = &bring_it ; // = std::addressof(bring_it); // http://en.cppreference.com/w/cpp/memory/addressof
    pointer->Eatsomething();

    Thisthing this_thing ;
    pointer = &this_thing ; // = std::addressof(this_thing);
    pointer->Eatsomething();
}

http://coliru.stacked-crooked.com/a/4d912b9fd384fdeb

[Blackhart98]

So there is pretty much no way of doing it like I said it I knew it. But yeah I actually have defined it by refrence before hand. Thanks anyway @JLBorges

[dhayden]

You asked for a way to do it with one pointer and JLBorges showed an example of doing that. Are you asking if there is a way to access both functions through a single object? You can't do that. The reason is that with virtual functions, the function that gets called is basically a property of the object itself.

[MiiNiPaa]

Are you asking if there is a way to access both functions through a single object? You can't do that.

You can if you want.

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#include <iostream> class Thisthing { public: virtual void Eatsomething() { std::cout << "He is being eaten\n"; } private: int Dont_Eat_Him; }; class Bringit : public Thisthing { public: void Eatsomething() { std::cout << "He's going to be ate\n"; } }; int main() { Thisthing *p = new Thisthing; Bringit *u = new Bringit; p->Eatsomething(); std::cout << '\n'; u->Eatsomething(); u->Thisthing::Eatsomething(); }

He is being eaten He's going to be ate He is being eaten

[Blackhart98]

Thanks @MiiiNiPaa that is exactly what I was looking for.