quotient
There is no quotient function for two double-s? remquo doesn't round to nearest zero. I have to use fmod in indirect way.
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#include <iostream>
#include <iomanip>
#include <cfenv>
#include <cmath>
int main()
{
std::cout << std::fixed << std::setprecision(2) ;
#pragma STDC FENV_ACCESS ON // standard C99 pragma, ignored by clang++, g++, and msvc++
std::fesetround( FE_TOWARDZERO ) ; // the first call to fesetround() appears to be supported by all three compilers
std::cout << "FE_TOWARDZERO: " << 99.0 / 5.0 << ", " << 99.0 / -5.0 << " => "
<< std::nearbyint( 99.0 / 5.0 ) << ", " << std::nearbyint( 99.0 / -5.0 ) << '\n' ;
std::fesetround( FE_TONEAREST ) ; // but only the microsoft compiler appears to support subsequent calls
std::cout << " FE_TONEAREST: " << 99.0 / 5.0 << ", " << 99.0 / -5.0 << " => "
<< std::nearbyint( 99.0 / 5.0 ) << ", " << std::nearbyint( 99.0 / -5.0 ) << '\n' ;
std::fesetround( FE_DOWNWARD ) ; // but only the microsoft compiler appears to support subsequent calls
std::cout << " FE_DOWNWARD: " << 99.0 / 5.0 << ", " << 99.0 / -5.0 << " => "
<< std::nearbyint( 99.0 / 5.0 ) << ", " << std::nearbyint( 99.0 / -5.0 ) << '\n' ;
}
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Microsoft:
http://rextester.com/RHFS31721
LLVM and GNU:
http://coliru.stacked-crooked.com/a/ade0720c6ea98fc1
No, but you can write your own easily enough:
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inline double iquotient( double n, double d )
{
return (n - fmod( n, d )) / d;
}
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I that what you meant?
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