call parent function from overriding function in child

[joecooler]

I have a class (child) that is inheriting from another class (parent). I'd like to create a function in the child class w/the same name and arguments as a function in the parent class, and have the child class call the function in the parent class before it (the child function) exits. What is the syntax to do this?

[TarikNeaj]

and have the child class call the function in the parent class before it (the child function) exits.

I dont know what this means. Please show us your code and explain further. And use code tags <> its under the format section.

[joecooler]

class parent {
public:
int test;
virtual function foo(int input) { test=input; }
}

class child : parent {
public:
int new_test;
virtual function foo(int input) { new_test=input; <call parent function foo here> }
}

so when you call child.foo, new_test and test are set to input.

[TarikNeaj]

I guess like this?

class Finish
{
public:
	int input;
	Finish(){}
	~Finish(){}

	virtual void foo(){ cout << "yo" << endl; }


};



class Tester : public Finish
{
	
public:
	Finish fin;
	void foo() { cout << "Hello" << endl; fin.foo(); }
};

Edit : oh I had no idea you could just do Finish:: to access its function, thats cool thanks @Keskiverto

[keskiverto]

No. The "fin" is a separate object. You want to call the method of this.

See http://stackoverflow.com/questions/672373/can-i-call-a-base-classs-virtual-function-if-im-overriding-it

[joecooler]

keskiverto you got it, and that syntax works. thanks!

[joecooler]

so i think my code should look like this:

class parent {
public:
int test;
virtual function foo(int input) { test=input; }
}

class child : parent {
public:
int new_test;
virtual function foo(int input) { new_test=input; parent::foo(input); }
}