User defined power function?

[nomanrasheed]

Hi,

I have coded this program.

  #include <iostream>
#include <math.h>
using namespace std;

int main()
{
	double x=0, y=0, v=0;

	cout<<"Enter base: ";
	cin>>x;
	cout<<"Enter exponent: ";
	cin>>y;

	while (x<999 && y<999)
	{
	v=pow(x,y);
	
	cout<<"Value: "<<v<<endl;
	
	cout<<"Enter base: ";
	cin>>x;
	cout<<"Enter exponent: ";
	cin>>y;
	}
	
	return 0;
}

Instead of using v=pow(x,y), I want to use v=n(x,y). How could I get that?

[TarikNeaj]

I have no idea what you're actually asking, could you give examples?

Do you mean you want to create a function called "n". That returns pow(x,y) which is then stored in the variable v?

[nomanrasheed]

Exactly! Instead of using pow(base, exponent). I want to create my own function with any variable. Like: a(b,c) or anything else.

[TarikNeaj]

Then do just that. Create a function, of type double/float.

It takes two integer as parameter.

And it returns the pow of them.

Then you call for it v = thatFunction(x,y)

and give it the two integers that it will work with.

Get started on this, and I'll help you out if you get stuck.

Edit: There are lots of answers on google, and videos on youtube explaining all of this :) Use it to your advantage.

[nomanrasheed]

Can you just give me some hints on how to start because I don't know how to create a function?

[TarikNeaj]

https://www.youtube.com/playlist?list=PLAE85DE8440AA6B83

Video 9-11 is about functions. You specifically want the one with multiple parameters.

(You can just google or youtube how to create functions man, questions like this are useless and are easily accessed on the internet)

[Peter87]

Do you want to allow the exponent to be any floating point numbers or just integers? The first is quite complicated, the latter is much easier.

[nomanrasheed]

Okay!

@Tarik: I have watched all these videos, but I couldn't understand anything. Maybe I am dumb!
Can you please help me with this program?

@Peter: Exponent should be integer, but I have no idea of how to do.

[jheard901]

Well, to get you started with making the function:

int n(int x, int y)
{

}

So to break this down, you declare the return type of a function first before you name it (so in this case, int is the return type). Then you name the function after that (n is the name of the function, but you can change to whatever suits your boat).

Finally, you declare any parameters you want the function to take in. Let's start with understanding parameters: a parameter can be any type of variable (an int, float, or whatever) that you want a function to take in and use with itself. So, in this function I have declared two parameters (an int named 'x', and an int named 'y' (these names can be whatever you want)).

Now, you will need to do the math inside the function setting up a variable to store the value of 'x'. From there, you should multiply that variable against itself 'y' times. A simple way to do this involves using a for loop and setting the variable using '*=' which means it will equal itself * another value.

And that is pretty much all there is to it!