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"if statement missing (" help

meringue96 (2)
My homework is due two days from now and I have been struggling with this error I can't seem to fix. We were to create a program that lets the user sign up and log in and I really don't know what's the problem with my code. There's also an error called "Compound statement missing }".

Lines 27 and 40 was said to have the "if statement missing (" error and line 94 had the "Compound statement missing }"

Please help. :(

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  #include<iostream.h>
#include<conio.h>
#include<string.h>

void main ()
{
	clrscr();
	char ans, un[30], pw[30], UN[30], PW[30], answ, FN[30], SN[30];
	int x, y;
	cout<<"Do you have an account? (y/n)";
	cin>>ans;
	if (ans=='y')
	{
		cout<<"Please log in.";
		cout<<"/nUsername: ";
		cin>>un;
		cout<<"/nPassword: ";
		cin>>pw;
		x=strcmp(un,UN);
		y=strcmp(pw,PW);

		if (x==0 && y==0)
		{
			cout<<"Log in successful. \n\n";
			cout<<"Welcome, "<<FN<<" "<<SN;
		}
		if else (x!==0)
		{
			cout<<"Log in error.\nUsername not found.";
		}
		if else (y!==0)
		{
			cout<<"Log in error.\nIncorrect password.";
		}
		else
		{
			cout<<"Log in error. Please try again.";
		}
	}
	if else (ans=='n')
	{
		cout<<"Would you like to sign up? (y/n)";
		cin>>answ;
		if (answ=='y')
		{
			cout<<"Enter first name: ";
			cin>>FN;
			cout<<"Enter last name: ";
			cin>>SN;
			cout<<"Enter desired username: ";
			cin>>UN;
			cout<<"Enter password: ";
			cin>>PW;
			cout<<"Thank you for signing up.";
			cout<<"Please log in.";
			cout<<"/nUsername: ";
			cin>>un;
			cout<<"/nPassword: ";
			cin>>pw;
			if (x==0 && y==0)
			{
				cout<<"Log in successful. \n\n";
				cout<<"Welcome, "<<FN<<" "<<SN;
			}
			if else (x!==0)
				cout<<"Log in error.\nUsername not found.";
			if else (y!==0)
				cout<<"Log in error.\nIncorrect password.";
			else
				cout<<"Log in error. Please try again.";
		}
		else if (answ=='n')
		{
			cout<<"Goodbye.";
		}
		else
		{
			cout<<"That's not a valid answer.";
			cout<<"\nJesus.";
			cout<<"\nThere are already choices there.";
			cout<<"\nCan't you see?";
			cout<<"\nUgh.";
		}
	}
	else
	{
		cout<<"That's not a valid answer.";
		cout<<"\nJesus.";
		cout<<"\nThere are already choices there.";
		cout<<"\nCan't you see?";
		cout<<"\nUgh.";
	}
	getch();
}
Last edited on
Peter87 (11220)
if else should be else if.
meringue96 (2)
I just changed all the if else to else if. I now have 8 errors..

Expression Syntax in lines 27 & 65
If statement missing } in lines 39 & 77
Misplaced else in lines 40 & 78
Compound statement missing in lines 100 and 101

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#include<iostream.h>
#include<conio.h>
#include<string.h>

void main ()
{
	clrscr();
	char ans, un[30], pw[30], UN[30], PW[30], answ, FN[30], SN[30];
	int x, y;
	cout<<"Do you have an account? (y/n)";
	cin>>ans;
	if (ans=='y')
	{
		cout<<"Please log in.";
		cout<<"/nUsername: ";
		cin>>un;
		cout<<"/nPassword: ";
		cin>>pw;
		x=strcmp(un,UN);
		y=strcmp(pw,PW);

		if (x==0 && y==0)
		{
			cout<<"Log in successful. \n\n";
			cout<<"Welcome, "<<FN<<" "<<SN;
		}
		else if (x!==0)
		{
			cout<<"Log in error.\nUsername not found.";
		}
		else if (y!==0)
		{
			cout<<"Log in error.\nIncorrect password.";
		}
		else
		{
			cout<<"Log in error. Please try again.";
		}
	}
	else if (ans=='n')
	{
		cout<<"Would you like to sign up? (y/n)";
		cin>>answ;
		if (answ=='y')
		{
			cout<<"Enter first name: ";
			cin>>FN;
			cout<<"Enter last name: ";
			cin>>SN;
			cout<<"Enter desired username: ";
			cin>>UN;
			cout<<"Enter password: ";
			cin>>PW;
			cout<<"Thank you for signing up.";
			cout<<"Please log in.";
			cout<<"/nUsername: ";
			cin>>un;
			cout<<"/nPassword: ";
			cin>>pw;
			if (x==0 && y==0)
			{
				cout<<"Log in successful. \n\n";
				cout<<"Welcome, "<<FN<<" "<<SN;
			}
			else if (x!==0)
			{
				cout<<"Log in error.\nUsername not found.";
			}
			else if (y!==0)
			{
				cout<<"Log in error.\nIncorrect password.";
			}
			else
			{
				cout<<"Log in error. Please try again.";
			}
		}
		else if (answ=='n')
		{
			cout<<"Goodbye.";
		}
		else
		{
			cout<<"That's not a valid answer.";
			cout<<"\nJesus.";
			cout<<"\nThere are already choices there.";
			cout<<"\nCan't you see?";
			cout<<"\nUgh.";
		}
	}
	else
	{
		cout<<"That's not a valid answer.";
		cout<<"\nJesus.";
		cout<<"\nThere are already choices there.";
		cout<<"\nCan't you see?";
		cout<<"\nUgh.";
	}
	getch();
}


Also, please don't mind the lines 94-97..
koothkeeper (429)
If you are using vi or vim, you can match your braces with the '%' character.
Peter87 (11220)
The not-equal-to operator is !=.
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