Math Basic question C++

[Dkob1]

Would this print out a+C+5 ?

  cout << int('a')+int('C')+int('5');

int x=17, y=15;    
cout << x+y/4;         // =20
cout << x%3+4;      //  =6
cout << 2*x+3;       //  =37
cout << x-2*y+3;    //  = -10 

Can someone check if they are correct?

[mutexe]

as a string? No.

[Dkob1]

thats all that is printed

[Dkob1]

I think its by int but all it said was:

3. cout << int('a)+int('C')+int('5');

[JLBorges]

Even with just 'a' + 'C', usual arithmetic conversions are applied and the two resultant integers are added.
https://msdn.microsoft.com/en-us/library/3t4w2bkb.aspx

#include <iostream>
#include <type_traits>

int main()
{
    static_assert( std::is_same< decltype( 'a' ), char >::value, "type of 'a' is char" ) ;
    static_assert( std::is_same< decltype( 'a' + 'C' ), int >::value, "type of 'a' + 'C' is int" ) ;
    static_assert( std::is_same< decltype( +'a' ), int >::value, "type of +'a' is int" ) ;
}

http://coliru.stacked-crooked.com/a/3592124273b5e0bc

[Dkob1]

It only gives one line to answer so I'm thinking that it is supposed to be more simple than that.

[Dkob1]

what happens to int('5')?

[mutexe]

It's printing out the integer value of the character '5'.

[JLBorges]

#include <iostream>
#include <type_traits>

int main()
{
    static_assert( std::is_same< decltype( 'a' ), char >::value, "type of 'a' is char" ) ;
    static_assert( std::is_same< decltype( 'a' + 'C' ), int >::value, "type of 'a' + 'C' is int" ) ;
    static_assert( std::is_same< decltype( +'a' ), int >::value, "type of +'a' is int" ) ;
    
    std::cout << 'a' << ' ' << +'a' << '\n'
              << 'C' << ' ' << +'C' << '\n'
              << "'a' + 'C' " << 'a' + 'C' << '\n' ;
}

clang++ -std=c++14 -stdlib=libc++ -O3 -Wall -Wextra -pedantic-errors main.cpp -lsupc++ && ./a.out
g++ -std=c++14 -O3 -Wall -Wextra -pedantic-errors main.cpp && ./a.out
a 97
C 67
'a' + 'C' 164
a 97
C 67
'a' + 'C' 164

http://coliru.stacked-crooked.com/a/85018d905fcf8bfa