Simple question regarding type conversion.

[ianh83]

This is quite basic regarding converting types. Can someone help me understand the difference between these two statements assuming x1 and x2 are of type DOUBLE..

int t = x1 + x2;
int t = int(x1 + x2);

Are they equivalent? Is the latter better practice for some reason? (I ask because way 2 is the example given in my book but I'm wondering why you wouldn't do it the first way to save typing as much).

[dhayden]

I think they are equivalent. Anyone else?

[JLBorges]

> Are they equivalent?

Yes, in effect. Both require a narrowing conversion from double to int.
int t = x1 + x2; results in an implicit conversion from double to int.
int t = int(x1 + x2); the conversion is explicit (functional cast notation).

There would be a difference if the expression x1 + x2 appeared in a braced-init-list - implicit narrowing conversions are not allowed in {} initialization
http://www.stroustrup.com/C++11FAQ.html#narrowing
http://coliru.stacked-crooked.com/a/3c566e5ca3e334bc

[ianh83]

Thanks for the help