static_cast<char>

[happy11]

Write your question here.

[code]
Put the code you need help with here.
if (num==17)
cout << "Number output is: 'H' "<< endl;
if (num==18)
cout << "Number output is: 'I' "<< endl;
if (num==19)
cout << "Number output is: 'J' "<< endl;
if (num==20)
cout << "Number output is: 'H' "<< endl;

else if (num >= 20 && num <= 35) // else if the number is greater than or equal to 20 and number is less than or equal to 35//
cout << static_cast<char>('H' + (num - 10)) << endl;

___________________________________________________________
cout << static_cast<char>('H' + (num - 10)) << endl;

How does this static_cast operate? 'H' + num-10 ? Is this taking 10 from the number entered?
could someone help me with this question? I know static_cast rounds the number, but letters? How does the program know to output the next char once the number is input?

[Ispil]

What happens is that it takes the numerical value of 'H', implicitly casts it to int, adds num - 10, and then takes that new value and re-casts it into a character for displaying.

[Peter87]

static_cast is used for converting one type into another. 'H' is char but when you have char + int the result will be an int. You don't want to print the value as an integer (ASCII value) so you convert it into a char to make it print the value as a character.

[happy11]

Thanks you guys are a life saver :)