Testing each array

[darkn3ss]

The program below will generate 5 random numbers and asks the user to enter 5 numbers to see how many numbers he guessed right. What i need help is how do i test each array that the enter inputted, with the numbers the computer generated, with a loop without having both of the index increasing so i can test each individual index with the computer generated numbers 5 times before moving on to the next index for the user inputted index

srand(time(0));
	int number[5];
	//store each index with a random number
	for (int x = 0; x < 5; x++)
	{
		number[x] = rand()%5;
	}
	int userNumber[5];
	int right = 0;
	cout << "The computer just generated 5 numbers. Lets test your luck. Please enter 5 numbers: ";
	//input for user 5 numbers
	for (int x = 0; x < 5; x++)
	{
		cin >> userNumber[x];
	}
	//the test
	for (int x = 0; x < 5; x++)
	{
		if (userNumber[x] == number[x])
		{
			right++;
		}

	}
	//the random numbers
	for (int x = 0; x < 5; x++)
	{
		cout << number[x] << ',';
	}
	//results
	cout << "You got " << right << " right!";
	cout << "The numbers were: ";

i can write the test like this:
for (int x = 0; x < 5; x++)
{
if (userNumber[0] == number[x])
{
right++;
}

if (userNumber[1] == number[x])
{
right++;
}
if (userNumber[2] == number[x])
{
right++;
}
}
where i state out the index number but it would take forever if i had 10000 values.

[QWERTYman]

You could use a nested for loop:

for(int x = 0; x < 5; x++)
    for(int y = 0; y < 5; y++)
    {
        if(userNumber[i] == number[j])
            right++;
    }

But I'm not really sure this is what you want--if the user matches all five numbers, he will be told he got 25 right. What behavior are you trying to produce?

[darkn3ss]

Ohhh that worked. ty