How do I add 3-limit attempts for inputting my password?(with code)


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#include<iostream> 
#include<string> 
#include<cctype> 
#include<cstdlib> 

using namespace std; 

#include<conio.h> 
#include<windows.h> 

void counting(); 
void palindrome(char sal[120]); 
void password(string); 
char menu(); 
void quit(); 
string EnterPassword(); 

int main() 
{ 
	//add all your code here
	string pwd= EnterPassword();
	password(pwd);
	
	char answer;
	char option=menu();
	do
	{
	switch(option)
	{
        case 'a':
            char alt[120];
            palindrome(alt);
            break;
        case 'b':
            counting();  
			break;
		case 'c':
			quit();        
    }
    bool ans=true;
    answer=tolower(answer);
    while(ans)
    {
    	cout<<"\nDo you want to try again?[y/n] ";
    cin>>answer;
    try{
    if(ans!='y'||ans!='n')
    	throw ans;
    }
    catch(char a){
    	continue;
    }
	}
	ans=false;
	}while(answer!='n');
	cout<<"Thank you for your time, goodbye!\n";
	system("pause");
	return 0;
} 
void counting() 
{ 
	//add all your code here
    string sentence;
    getline(cin, sentence);
    
    
    int count[26]={0};
    
    for (int i = 0; i < sentence.length(); i++) 
        if (isalpha(sentence[i]) && islower(sentence[i]))
            count[sentence[i] - 'a']++;
    
	for (char c=0;c<26;c++) 
        if (count[c] != 0)
            cout<<char (c + 'a')<<": "<<count[c]<<endl;
	
} 
void palindrome(char sal[120]) 
{ 
	//add all your code here 
	system("cls");
	char rev[120];
	cout<<"          Palindrome Checker\n"
	    <<"----------------------------------------\n";
	cout<<"Please enter a word: ";
	cin>>sal;
	
	sal=strlwr(sal);
	strcpy(rev,sal);
	strrev(rev);
	
	bool palindrome=true;
	for(int i=0;sal[i]!='\0';i++)
		if(sal[i]!=rev[i])
		{
				palindrome=false;
				break;
		}
		
    if(palindrome==true)
        cout<<sal<<" is a palindrome.\n";
    else
        cout<<sal<<" is not a palindrome.\n";
} 
void password(string pw) 
{ 
	//add all your code here 

		system("cls");
		if(pw!="12345")
		{	
			cout<<"Processing your password";
			for(int i=0;i<4;i++)
			{
				Sleep(300);
				cout<<".";
			}
			cout<<"Invalid password. Please enter the correct password.\n";
		}
	  cout<<endl; 
} 
char menu() 
{ 
	//add all your code here
    system("cls"); 
	char option;
	cout<<"                Welcome!\n"
	    <<"----------------------------------------\n"
	    <<"[a] Check the palindrome.\n"
	    <<"[b] Read in a line of text.\n"
	    <<"[c] Quit.\n\n";
	    
	bool ans=true;
	while(ans)
	{
       cout<<"Enter your option: ";
	   cin>>option;
	   cin.ignore();
	   cout<<endl;
	   option=tolower(option);
	   try
	   {
            if(option!='a'&&option!='b'&&option!='c')
                throw option;
       }//end catch
       catch(char x)
       {
            cout<<"Wrong option! Enter again(a-c only).\n";
            continue;
       }//end catch
       ans=false;
    }//end while
    return option;
} 
void quit() 
{ 
	//add all your code here 
	char answer; 
	do{ 

		cout<<"\nAre you sure you want to quit[y/n]? ";
		cin>>answer; 
		answer=tolower(answer); 
	}while(answer!='y'&& answer!='n');
	if(answer!='y') 
    	main(); 
	else 
	{   
		cout<<"Thank you for your time. Good bye...\n"; 
		system("pause"); 
		exit(1); 
	}    
} 

string EnterPassword() 
{ 
	//add all your code here 
	
	string password="";
	cout<<"Enter password: "; 
   	char ch=getch();
   	 while(ch != '\r')
    { 
        ch = getch(); 
        if(ch == '\b')  
            { 
            if(password.size() != 0)
               { 
               cout << "\b \b"; 
               password.erase(password.size() - 1, 1); 
               } 
            continue; 
            } 
         else if(ch<='9'&&ch>='0'||ch>='a'&&ch<='z'||ch>='A'&&ch<='Z') 
            { 
            password += ch; 
            cout<<"*"; 
            } 
         else
            continue; 
         } 
	cout<<endl;
   return password;
}  
Ask in a loop. Correct answer gets you out from the loop immediately. Have a counter that increases on every iteration (i.e. wrong answer) and make the loop end after third failure.
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