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Invalid Conversion Error

psychoticbear (29)
Hey guys,

I'm in the middle of writing a program, but I came across this error that I can't seem to fix.

At line 155, the error is:
"invalid conversion from 'char (*)[3][20]' to 'char' [-fpermissive]"

Can anyone tell me what's wrong? Also, at line 186, this comes up:
array subscript has type 'char' [-Wchar-subscripts]

How can I fix this?

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  # include <iostream>
# include <iomanip>
# include <cctype>

using namespace std;

char get_menu_choice(char choice);

char sell_seat(char seats[][3][20]);
void print_chart(char seats[][3][20]);
/*
 void cashier(int var_2);
 void print_day_list(int var_4);
 void print_section_list(int var_5);
 */

const int MAX_DAYS = 3;
const int MAX_SECTIONS = 3;
const int MAX_SEATS = 20;

int main()
{
	char choice;
	char seats[3][3][20];

	cout << "Initializing seating chart." << endl << " " << endl;

	int d, s, n;
	for (d = 0; d < MAX_DAYS; d++) {
		for (s = 0; s < MAX_SECTIONS; s++) {
			for (n = 0; n < MAX_SEATS; n++)
				seats[d][s][n] = '-';
		}
	}

	cout << "All seats have been initialized." << endl << " " << endl;

	do {
		choice = get_menu_choice(choice);
		choice = toupper(choice);

		switch (choice) {
		case 'S':
			sell_seat(seats);
			break;

		case 'C':
			cout << "You chose C!" << endl;
			break;

		case 'D':
			cout << "You chose D!" << endl;
			break;

		case 'F':
			cout << "You chose F!" << endl;
			break;

		case 'Q':
			cout << "Quit" << endl;
			break;

		default:
			cout << "Invalid selection. Try again." << endl;
			break;
		}

		cout << " " << endl;
	} while (choice != 'Q');

	return 0;
}

char get_menu_choice(char choice)
{
	cout.fill(' ');
	cout << setw(22) << "*** Main Menu ***" << endl
			<< "S - Sell a Ticket." << endl
			<< "C - Display Seating Chart." << endl
			<< "D - Display Sales Summary - Day Listing" << endl
			<< "F - Display Sale Summary - Floor Listing" << endl
			<< "Q - Quit"<< endl
			<< "Your Choice: ";

	cin >> choice;

	return choice;
}

char sell_seat(char seats[][3][20])
{
	int d, s, n;
	char day;
	char section;
	int num;
	d = MAX_DAYS;
	s = MAX_SECTIONS;
	n = MAX_SEATS;

	//seats[d][s][n] = '-';

	cout << "Enter seat request by day (T)hursday, (F)riday, or (S)aturday"
			<< endl
			<< "followed by section (F)loor, (B)alcony, or (U)pper Balcony"
			<< endl << "followed by seat number (1 - 20)." << endl;
	cout << "Seat: ";
	cin >> day;

	day = toupper(day);
	switch (day) {
	case 'T':
		d = 0;
		break;
	case 'F':
		d = 1;
		break;
	case 'S':
		d = 2;
		break;
	default:
		cout << "Invalid choice try again";
		break;
	}

	cin >> section;
	section = toupper(section);
	switch (section) {
	case 'F':
		s = 0;
		break;
	case 'B':
		s = 1;
		break;
	case 'U':
		s = 2;
		break;
	default:
		cout << "Invalid choice try again";
		break;
	}

	cin >> num;
	if (n < 0 || n > 20)
		cout << "Invalid seat number." << endl;
	else
		n -= 1;

	if (seats[d][s][n] == '*')
		cout << "This seat has been taken." << endl;
	else {
		seats[d][s][n] = '*';
		cout << "Congratulations! You got the seat." << endl;
	}

	return seats;
}


void print_chart(char seats[][3][20])
{
	char d, s;
	int n;
	for (d = 0; d < 3; d++)
	{
		switch (d)
		{
		case 0: cout << "Thursday" << endl;
		break;
		case 1: cout << "Friday" << endl;
		break;
		case 2: cout << "Saturday" << endl;
		break;
		}
		for (s = 0; s < 3; s++)
		{
			switch (s)
			{
			case 0: cout << "Floor: " << endl;
			break;
			case 1: cout << "Balcony: " << endl;
			break;
			case 2: cout << "Upper Balcony: " << endl;
			break;
			}
			for (n = 0; n < 20; n++)
				cout << seats[d][s][n];
		}
	}
}
psychoticbear (29)
I figured out the error on line 155, but there's still line 186.
JewelCpp (87)
for the first question:the answer:
the return type of the function is char however you are returning seats which is of type char[][3][20] which are not compatible cause the second is like a triple pointer
for the second I didn't understood what is the problem -if any-
JewelCpp (87)
what is the whole message for error at line 155
AbstractionAnon (6954)
Line 161: d and s are type char. Your compiler is warning you of unconventional usage. Everywhere else in your program, d and s are ints.
I don't see a reason why d and s should be type char.
psychoticbear (29)
I had already figured out line 155 (I set my program up not to return anything, since the array updates anyways).

And actually, I can't remember why I had set d and s to be char. It must have been from before I edited the code. Anyways, it's fixed now. Thanks guys.
Last edited on
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