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Arrays

JustJoeKing (2)
I am starting to work with arrays. I was given this problem. adding 20 digit arrays.

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#include <iostream>
#include <string>
using namespace std;

void convert();
void addnum();
void print();
void printSum();
void addarrays();

int first[20] = { 0 };
int second[20] = { 0 };
int sum[21] = { 0 };
int lengthF;
int tempLenF;

int main()
{
	convert();
	addarrays();
	//print();
	printSum();
}

void convert()
{
	string num1;
	string num2;


	std::cout << "Please enter the first positive integer (20 digits at the most): " << endl;
	cin >> num1;

	if (num1.size() > 20)
	{
		cout << "Your First number has more than 20 digits. Pleases Try Again.";
		exit(0);
	}

	std::cout << "Please enter the second positive integer (20 digits at the most): " << endl;
	cin >> num2;

	if (num2.size()>20)
	{
		cout << "Your First number has more than 20 digits. Pleases Try Again.";
		exit(0);
	}

	int count = 0;

	for (int i = (int)num1.length() - 1; i >= 0; i--)
	{
		first[count] = num1[i] - '0';
		count++;
	}

	int count2 = 0;

	for (int i = (int)num2.length() - 1; i >= 0; i--)
	{
		second[count2] = num2[i] - '0';
		count2++;
	}


	if (num1.size()>num2.size())
		lengthF = num1.size();
	else if (num2.size()>num1.size())
		lengthF = num2.size();

}

void addarrays()
{
	int carryover = 0, temp = 0;

	for (int i = 0; i <= 20; i++)
	{
		temp = carryover + first[i] + second[i];

		if (temp > 10)
		{
			carryover = 1;
		


/*
void addnum()
{
//addition is the number carried on
int addition = 0;
int temp;
int i;
int sumcount = 20;
for (i = 0; i<lengthF; i++)


//Temp is starting from the right of the number and calulates the simple addition of 10
temp = first[i] + second[i] + addition;
if (temp>10)
{
addition = 1;
temp = temp - 10;
sum[sumcount--] = temp;
}
else
{
addition = 0;
sum[sumcount--] = temp;
}
if (i == lengthF - 1)
{
sum[sumcount] = addition;
}
}
*/	temp -= 10;
		}

		sum[i] = temp;
	}

}


void print()
{

	int counterSum = 0;
	for (int i = 0; i < 21; i++)
	{
		if (sum[i] != 0)
		{
			counterSum = i;
			break;
		}
	}

	cout << "Sum = ";

	for (int i = counterSum; i < 21; i++)

	{
		cout << sum[i];
	}

	cout << endl;
}

void printSum()
{
	bool ignorezeros = true;


	for (int i = 21; i >= 0; i--)
	{

		if (sum[i] == 0 && ignorezeros)
		{

		}
		else
		{
			ignorezeros = false;
			cout << sum[i];
		}
	}
}
Last edited on
keskiverto (10402)
I see no question.
JustJoeKing (2)
Oh i meant to say that. It isnt out putting right. and i need help finding out the problem. Ex i enter 123 and 123 it should output 246 but it outputs 900000000000000246
keskiverto (10402)
Sum has 21 elements. First value that you do look at in printSum is sum[21]. That is an out of range error.
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