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Function parameter out of scope

dleanjeanz (105)
I have a function that writes the binary of a character (got it on stackoverflow.com):

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void binary(char c) {
   int remainder;

   if((int)c <= 1) {
       std::cout << (int)c;
       return;
   }
   remainder = (int)c % 2;
   binary((int)c >> 1);    
   std::cout << remainder;
}


I was trying to make a similar function that return the binary in a string:

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string Binary(const char& c) {
	int r;
	string out;
	
	if ((int)c <= 1) {
		out += (int)c;
		return "";
	}
	r = (int)c % 2;
	Binary((int)c >> 1);
	
	stringstream ss;
	ss << r;
	out += ss.str();
	return out;
}


The function might not be finished yet (I don't know does it work well) so I was debugging to finish it of course and I found that the identifier 'c' was out of scope wtf!!! Why??? And I want the function to be finished, too. Thanks.
Peter87 (11234)
You must have misinterpreted the information the debugger gave you. c is in scope throughout the whole function.
dleanjeanz (105)
Peter87 (11234)
No, your debugger is wrong it seems. Have you tried recompile everything to see if that makes the error go away?
dleanjeanz (105)
I think it's not gonna work.

UPDATED: And it did not work.
Last edited on
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