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Function Parameter Error

ldelsignore (57)
Hi, this program is supposed to output a table, which it does do. however, the values in the last column are incorrect. I think it has something to do with my function parameters, as the function calls use different variable names than those in the function declaration and definition. I have seen code where this is done, but I suspect that I am not doing it right.

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/* This program calculates the individual
  and total charges for three cars in a
  parking garage depending on how many
  hours each car was parked. The program
  takes in the data and outputs the charges
  in a table.
*/

#include <iostream>
using namespace std;
void CalculateCharge(double& hours, double& charge);

int main()
{

	double car1 = 0, car2 = 0, car3 = 0, charge1 = 0, charge2 = 0, charge3 = 0, TotalHours = 0, TotalCharge = 0;
	cout << "Welcome to the parking garage program." << endl;
	cout << "Enter the hours parked for three cars:" << endl;
	cin >> car1;
	cin >> car2;
	cin >> car3;
 	CalculateCharge(car1, charge1);
	CalculateCharge(car2, charge1);
	CalculateCharge(car3, charge1);
	TotalHours = car1 + car2 + car3;
	TotalCharge = charge1 + charge2 + charge3;
	cout << "Car" << "\t\t" << "Hours" << "\t\t" << "Charge" << endl;
	cout << "1" << "\t\t" << car1 << "\t\t" << charge1 << endl;
	cout << "2" << "\t\t" << car2 << "\t\t" << charge2 << endl;
	cout << "3" << "\t\t" << car3 << "\t\t" << charge3 << endl;
	cout << "Total" << "\t\t" << TotalHours << "\t\t" << TotalCharge << endl;

	return 0;
}

void CalculateCharge(double& hours, double& charge)
{
	if (hours > 3)
	{
		charge = 2 + (0.5 * (hours - 3));
	}
	else
	{
		charge = 2 + (0.5 * hours);

	}
}
Peter87 (11238)
Can you please give an example showing the program output and what output you expected.
jidder (139)
You have set all of the 2nd parameters to charge1

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	CalculateCharge(car1, charge1);
	CalculateCharge(car2, charge1);
	CalculateCharge(car3, charge1);


guessing thats where youre running into trouble

hope that helps :)
ldelsignore (57)
Thanks, that does help.
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