Question : Conversions
While loop not working. Please suggest
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#include<stdio.h>
#define p printf
#define s scanf
int num;
void showbits(int n);
void octal(int n);
void hexadecimal(int n);
int main()
{
int ch;
p("Enter number");
s("%d",&num);
p("Enter your choice:\nPress 1 for binary conversion\nPress 2 for octal conversion\nPress 3 for hexadecimal conversion");
s("%d",ch);
while(ch==1||ch==2||ch==3)
{
switch(ch)
{
case 1:
{
showbits(num);
break;
}
case 2:
{
octal(num);
break;
}
case 3:
{
hexadecimal(num);
break;
}
default:
{
p("\nInvalid Option");
break;
}
}
p("\nWhat do you want to do now?");
s("%d",&ch);
}
return 0;
}
void showbits(int n)
{
int i;
unsigned char j, k, andmask;
p("The binary conversion is ");
for(i=7;i>=0;i--)
{
j=i;
andmask=1<<j;
k=n&andmask;
k==0?p("0"):p("1");
}
}
void octal(int n)
{
p("The octal conversion is %o",n);
}
void hexadecimal(int n)
{
p("The hexadecimal conversion is %x",n);
}
|
Do you want help in C or help in C++? This program appears to be entirely written in C.
main.c:15:12: warning: format specifies type 'int *' but the argument has type 'int' [-Wformat]
s("%d",ch);
~~ ^~ |
You should always enable warnings when compiling.
Line 15 should pass the address of ch:
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