undefined reference to `swap'|

[Simon Izraev]

Hi all! it's my first time posting on this forum altho, I used it for a while now.
I tried to find the problem in my code when writing a simple swap function with pointers in C. but no matter what I do, im still getting same error.

undefined reference to `swap'|

#include <stdio.h>

int swap(int *a, int *b);
int main()
{
	int x, y;

	printf("Enter 2 integers:\n");
	scanf("%d %d", &x, &y);
	printf("%d %d\n", x, y);
	swap(&x,&y);
	printf("%d %d", x, y);
	return 0;


int swap(int *a, int *b)
{
 int tmp;

tmp = *a;
*a = *b;
*b = tmp;
return 0;
}


}

[coder777]

Define swap() outside of main(). After line 27

[Simon Izraev]

Tried to. didnt help. not at line 27 nor before main. same Error.

[Peter87]

Yeah, the problem is that you can't define functions inside other functions.

[Simon Izraev]

Thank you coder77 and peter87. I defined it outside the main function in the proper way. it's working now.

[coder777]

what compiler do you use? There should be a comiler error when swap() is defined inside main().

If you define swap() outside main() the linker should be satisfied except there's a typo in the definition.

By the way: line 20 is wrong it should be tmp = *a;

[Simon Izraev]

Nah, i just defined it wrong. after few tries and some google. i defined it in the proper way. and about line 20: yeah i figured it out after i compiled correctly.
thank you very much for your help.