Q3.Problem

[Sharan123]

Q.3. Why does decleration of char with out pointer
datatype causes error for example

  const char suitNames[] = {"Clubs ", "Diamonds ", "Spades ", "Clubs "};//causes error
const char* suitNames[] = {"Clubs ", "Diamonds ", "Spades ", "Clubs "};//doesnt cause error 

[firedraco]

The first creates an array of constant characters. "Clubs", etc are not const char, they are const char*s.

[Sharan123]

Yes but why isnt the first const char for example "Clubs" is intialized why should there be need for pointer storing and int storing will cause an error

[keskiverto]

const char suitNames[4]; is an array of four characters. Each element in the array is a const char. char is a datatype that holds one character. One byte.

"Diamonds " is not a single charater. It is an array or characters. If you need an array of arrays, then an array of single characters just doesn't suit you.

[veektorh]

We use ' ' for chars
And " " for strings
BTW chars is for characters not words

[Sharan123]

Yes you made the array point clear for me but i understand the use for pointer in it now it's been made clear by you to me that const char suitNames[] is reqired but why this will cause error instead we should write const char * suitNames[]

[keskiverto]

Lets forget the array. Lets take just one value. You would like to write const char name = "fubar"; but that does not work. Why?

You are attempting to store the address of a constant string literal (which are stored in memory space of their own) into a variable that does store one character. An address of a memory location is not same as a char.

[Sharan123]

You are attempting to store the address of a constant string literal (which are stored in memory space of their own) into a variable that does store one character. An address of a memory location is not same as a char.

Did you mean char has a memory of 1 byte and it will not store const char vaariable but it will do so if its a const char pointer variable

[keskiverto]

No.

A char variable stores one character.
A pointer variable stores one pointer.

[Sharan123]

Thank you its clear now :)