Analyzing lists of random numbers

[LM96]

What I need to do is wait until 5 of a certain type of number appear consecutively and then begin a counter according to what numbers appear after.

I'm new to c++ so any help would be lovely.

Only have this so far.

#include <iostream>
#include <ctime>

using namespace std;


int main()
{
	time_t t;
	time(&t);	
	srand(t);
	
	rand() % 37 + 1;

	for (int iIndex = 0; iIndex < 100; ++iIndex) {
		cout << (rand() % 37 + 1) << "\t";
	}
}

[LM96]

bump

[LM96]

bump x two

[metulburr]

What I need to do is wait until 5 of a certain type of number appear consecutively and then begin a counter according to what numbers appear after.

I do not quite understand exactly what you are trying to accomplish? Maybe you can elaborate more.

[Ganado]

What I need to do is wait until 5 of a certain type of number appear consecutively and then begin a counter according to what numbers appear after.

I think I understand what you mean, at least for your first statement about 5 numbers appearing consecutively.

I'll show you some code that partially does the first part of your problem:

#include <iostream>
#include <ctime>
#include <cstdlib> // needed for the rand and srand to work
#include <vector> // I used vectors to keep track of the values displayed

using namespace std;

int main()
{
    time_t t;
    time(&t);	
    srand(t);

    vector<int> values;

    for (int iIndex = 0; iIndex < 100; iIndex++)
    {
        int random_value = (rand() % 37 + 1);
        cout << random_value << "\t";
		
        values.push_back(random_value);
	
    }
	
    for (int jIndex = 0; jIndex < 100; jIndex++) 
    {
        if ( values[jIndex] == values[jIndex + 1] && values[jIndex + 1] == values[jIndex + 2] )
        {
            // i.e. if a = b and b = c, then a = c
            cout << "3 adjacent numbers repeat in this randomized output!" << endl;
        }
    }
}

(The "100" in the code is the number of random digits between 1 and 37 that are output.)

This code could probably be simplified, but it does the job. This code will display a message for each time 3 adjacent random integers are the same value. Add more && operators at line 27 to make the condition only make the message display if 4 adjacent numbers repeat, or 5, or beyond.

The program is currently limited by the 100, and it currently displays all 100 values (doesn't stop displaying even if there is a adjacent-value chain half-way through the output list). You also may have to run the program multiple times for 3+ digits to repeat within 100 digits, since the chances of that happening are less than 1/100.

I probably won't, but if I have more time for this, I'll try to do the next part.

[LM96]

Thanks ganado, ill try out the code when i get home. Metal, what i wanna do is wait until three numbers from 1-17 appear consecutively. So if it generates 5, 5, 14 then i record what happens to the next 10 numbers... Same thing if 18-36 are drawn.