confusion with comparison of char

[Ramzi89]

Why is this output as true. Arn't 0 and 9 converted to their ascii equivalents and numbers are lower in ASCII so 9 is not lower?

 ch3 = 'C';

cout << "'0: " << ('0' < ch3 < '9') << endl;

[Catfish4]

You can't chain comparisons like that.

What you probably want is:

'0' < ch3 && ch3 < '9'
// or
'0' < ch3 and ch3 < '9' // although this may raise some eyebrows 

What I think happens in your original code is:
1) '0' < ch3 gets evaluated to true which is 1.
2) 1 < '9' gets evaluated to true

[keskiverto]

Relational operators are evaluated from left to right. '0' < foo < '9' is about same as

bool tmp = '0' < foo;
tmp < '9'

[Ramzi89]

cool cool makes perfect sense. Thankyou.