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cosa nostra (23)
We have 2 fields - 6 numbers. Summing up homotopy elements and stores them in the third field.

2 5------> 7
3 5------>8
4 11------>15

Fransje (435)
what are homotopy elements?
cosa nostra (23)
the number which are in the same position
keskiverto (10402)
Could you show the part of your code that you have problems with?
cosa nostra (23)
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#include <iostream>	// vhodno-izhodni ukazi
#include <stdlib.h> //standardni ukazi
#include <string> // za la?je delo z nizi, veljavno le v C++ in ne v C#
#include <iostream>
using namespace std;
 
int main()
{
    int polje1[6];
    int polje2[6];
    int polje_vsot[6];
 
    cout<<"Vnesite elemente prvega polja: "<<endl;
     
    for(int i=0; i<6; i++)
        cin>>polje1[i];
 
    cout<<"Vnesite elemente drugega polja: "<<endl;
 
    for(int i=0; i<6; i++)
    cin>>polje2[i];
 
 
    short rezultat;
    //Sestevanje istoležnih elementov v obeh poljih
    for(int i=0; i<6; i++)
    {
        rezultat = polje1[i] + polje2[i];
        
    }
    
    cout<<"REZILTAT"<<rezultat<<endl;
    system("pause");
    return 0;
}




how to display the result in reverse order
keskiverto (10402)
Why is resultat a short? You do store a sum of ints to it.

The loop on lines 26-30 could be replaced with rezultat = polje1[5] + polje2[5]; because that is what you effectively do in it.

You don't use polje_vsot anywhere.

Reverse? How about for (int i=5; 0<=i; --i). It's crude, but could suffice.
cosa nostra (23)
example.

1 2 result 3
2 3 5
3 11 14
4 1 5
5 1 6
6 12 18


result on display - 18 -6-5-14-5-3 (reverse order)
cosa nostra (23)
THIS IS RESULT.
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#include <cstdlib>
#include <iostream>


using namespace std;
 
int main()
{
    int polje1[6];
    int polje2[6];
    int polje_vsot[6];
    int rezultat;
 
    cout<<"Vnesite elemente prvega polja: "<<endl;
     
    for(int i=0; i<6; i++)
        cin>>polje1[i];
 
    cout<<"Vnesite elemente drugega polja: "<<endl;
 
    for(int i=0; i<6; i++)
    cin>>polje2[i];
    
 
    //Sestevanje istoležnih elementov v obeh poljih
    for(int i=0; i<6; i++)
    {
        rezultat= polje1[i] + polje2[i];
        polje_vsot[i] = rezultat;
    }
 
   
   
   for(int i=6; 0<i; )
  {
    i=i-1;
    cout<<"resitev izpisane  v obratnem vrstnem redu"<<polje_vsot[i]<<endl;  
     
  }
   
    system("pause");
    return 0;
}


which field have a large sum?
how is code ?

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