EXCEPTION HANDLING QUESTION

[Abdullah PAKISTANI]

in this code although i have a general catch block but when i try to enter a double value instead of integer one the program runs infinitely what to do???

  /////////////////////////////////////////////////////////////////////////////////////////////////////////

#include <iostream>
using namespace std;

void main(){
	while(1){	try{
cout<<"Enter the dividend ";
int x;
cin>>x;

cout<<"Enter the divisor ";
int y;
cin>>y;

if(y==0)
throw 0;

int ans;

ans = x
/y;

cout<<"\nDivision gives result : "<<ans<<endl;
	}
	catch(int){
		cout<<"\n\ndivisor wrongly entered as 0 re enter please\n\n";
	}

	catch(...){

	}

}
}



//////////////////////////////////////////////////////////////////////////////////////////////////////// 

[Bourgond Aries]

What I do first is to indent the code to make it readable.
I believe entering a double into an int yields undefined behaviour, so we promote int to double.

#include <iostream>
using namespace std;

int main()
{
    while(1)
    {
        try
        {
            cout<<"Enter the dividend ";
            double x;
            cin>>x;

            cout<<"Enter the divisor ";
            double y;
            cin >> y;

            if(y == 0.)
            throw 0;

            int ans;

            ans = x
            /y;

            cout<<"\nDivision gives result : "<<ans<<endl;
        }
        catch(int)
        {
            cout<<"\n\ndivisor wrongly entered as 0 re enter please\n\n";
        }
        catch(...)
        {

        }
    }
}

[Abdullah PAKISTANI]

can we also handle exception when user enters values other than this approach

[Bourgond Aries]

Any way you like.

[Peter87]

cin does not throw exceptions by default.
You can do cin.exceptions(ios::failbit); to enable exceptions.

[Abdullah PAKISTANI]

i want to say like we are entering values into an int type of variable and the user enters a double type value than we prompt our user that you have entered a wrong value and you should enter an integer value....

CAn we do this if yes than kindly show how to do

[Bourgond Aries]

Input into a string. Convert to int.
See documentation of std::stoi(std::string &); @ http://en.cppreference.com/w/cpp/string/basic_string/stol

#include <iostream>
using namespace std;

int main()
{
    while(1)
    {
        try
        {
            std::string x, y;
            cout<<"Enter the dividend ";
            cin>>x;

            cout<<"Enter the divisor ";
            cin >> y;

            if(!std::stoi(y))
                throw 0;

            int ans;

            ans = std::stoi(x)/std::stoi(y);

            cout<<"\nDivision gives result : "<<ans<<endl;
        }
        catch(int)
        {
            cout<<"\n\ndivisor wrongly entered as 0 re enter please\n\n";
        }
        catch(...)
        {

        }
    }
}

[Abdullah PAKISTANI]

got it THANKS