*s vs s in a function

[codemunchkin]

In the "myPrintf" function below (which runs correctly when called), I don't understand how it takes a const char * (pointer) as a parameter but then drops the star (*) in the function definition. Isn't that a change from pointer to a memory address??

[code]
#include <stdarg.h>
int myPrintf(const char *s, ...)
{
    va_list arguments;
    va_start (arguments, s);
    int c = 0;
    c = vprintf(s, arguments);
    return c;
}

int main()
{
    myPrintf("Hello %d\n", 1234);
    return 0;
}

[keskiverto]

's' is a name of variable that is a pointer. The va_start and vprintf look like functions, and functions can take pointer as parameter (myPrintf is an example of that).

If you would write *s in statement, you would be calling the dereference operator. Then you would not pass a pointer, but the value pointed to by the pointer.