How can i show binary values in editbox?

[Helegurbann]

I want to show a file binary values in textfield2.Thank u for ur all helps.

#include <fstream>
#include <windows.h>
#include <bitset>
#define textfield1 0
#define textfield2 1
#define push 2
#define label 3
#define label2 4
using namespace std;
LRESULT CALLBACK P(HWND A,UINT B,WPARAM C,LPARAM D){
       switch(B){case WM_CREATE:
                       CreateWindow("edit","",WS_CHILD|WS_VISIBLE,5,50,980,700,A,(HMENU)textfield1,NULL,NULL);
                       CreateWindow("edit","",WS_CHILD|WS_VISIBLE,55,10,786,25,A,(HMENU)textfield2,NULL,NULL);
                       CreateWindow("static","Adress:",WS_CHILD|WS_VISIBLE,5,10,50,25,A,(HMENU)label,NULL,NULL);
                       CreateWindow("static","This File Binary codes:",WS_CHILD|WS_VISIBLE,5,35,170,15,A,(HMENU)label2,NULL,NULL);
                       CreateWindow("button","Show Binary Codes",WS_VISIBLE|WS_CHILD,845,10,140,25,A,(HMENU)push,NULL,NULL);
                       break;
                       case WM_COMMAND:
                            switch(LOWORD(C)){
                            case push:
                                 char *adress,*b;
                                 GetDlgItemText(A,textfield1,adress,TRUE);
                                 ifstream file;
        file.open(adress,ifstream::binary);
        long filesize;
       file.seekg(0,ifstream::end);
        filesize=file.tellg();
        file.seekg(0);
        b=new char[filesize];
        file.read(b,filesize);
        for(int i=0;i<filesize;i++){
                bitset<8>binary(b[i]);
                for(int j=0;j<8;j++){
                if(!SetDlgItemInt(A,textfield2,binary[j],TRUE))
                MessageBox(NULL,"Not Success binary convert","ERROR",MB_OK|MB_IConerror);
                }
                }
                break;
                }
                            break;
                  case 0x2:
                       PostQuitMessage(0);
                       break;
                       default:
                               return DefWindowProc(A,B,C,D);
                  }
        return 0;}
        char title[]="File Binary Codes";
int WINAPI WinMain(HINSTANCE A,HINSTANCE B,LPSTR C,int d){
    HWND E;
    MSG F;
    WNDCLASS G={0};
    G.hInstance=A;
    G.lpszClassName=title;
    G.lpfnWndProc=P;
    G.lpfnWndProc=P;
    G.hbrBackground=GetSysColorBrush(COLOR_3DFACE);
    RegisterClass(&G);
    CreateWindow(G.lpszClassName,title,0xcf0000|WS_VISIBLE,50,10,1000,800,0,0,A,0);
    while(GetMessage(&F,NULL,0,0)){
                        TranslateMessage(&F);
                        DispatchMessage(&F);
                        }
                        return F.wParam;
    }

[webJose]

Feeding an edit control with binary data is not useful because it is unable to present control codes and such. The best advice I can give: Make a string representation of the binary data, and show that in the edit control.

Basically take each byte in the binary data and transform it to its hexadecimal representation using a std::stringstream object (or std::wstringstream). This pretty much is what you see others do out there, including MS SQL Server when showing a Select on a binary or varbinary field.

[Helegurbann]

Ok.I understand this.But binary[j] UINT.It must be this.I don't understand this.
If i make this:

char *c;
b<<binary;
c=b;
SetDlgItemText(A,textfield2,c);

Is this run?