How do you convert char [11] to int [10]

[HenryJ]

I have this bit of code here:

char answer1[11];
int answer2[10];
...
for(initializer=0;initializer<10;initializer++)
answer2[initializer]=atoi(answer1[initializer2]);
...

and it comes up with the following errors:

C:/C++/Projects/Base_converter_calculator/Calculation.cpp:27: error: invalid conversion from 'char' to 'const char*'
C:/C++/Projects/Base_converter_calculator/Calculation.cpp:27: error: initializing argument 1 of 'int atoi(const char*)'

Can somebody help me?

[award982]

why dont you just use something like

int answer[10];
for(int x = 0; x<=10;x++){
cin.get(answer[x]); //afaik this should return just one value, could be wrong though.
}

you can also use

#include <conio.h>

int answer[10];
for(int x = 0; x<=10;x++){
answer[x] = getch() - '0';
}


both of these examples would just get the integers straight from the input of the keyboard.

Or do you need it for some other purpose?

[quick]

do not use function atoi(), because this function takes a const char * as parameter, but you give a char in your program. You can change the statement answer2[initializer]=atoi(answer1[initializer2]);
to
answer2[initializer]= answer1[initializer2] - '0';
I think it will work fine.

[HenryJ]

quick, your code worked perfectly first time but when I use it like this:

int answer1[10];
int answer3[10];
char answer2[11];
char answer4[11];
for(i1=0;i1<10;i1++)
answer1[i1] = 0;
for(i2=0;i2<10;i2++)
answer2[i2] = 0;
for(i3=0;i3<10;i3++)
answer3[i3] = 0;
for(i4=0;i4<10;i4++)
answer4[i4] = 0;
...
answer1[i1]= answer2[i2] - '0';
answer3[i3]= answer4[i4] - '0';
...

answer2 and answer4 are numbers in a character state. answer1 and answer 3 would be a random number near answer2 and answer4.
Can somebody help?

[komp11]

First of all, you are converting 1 byte to 4 byte array. So try this....

char a1[11];
int a2[10];


for (int i=0;i<10;i++)
{
memcpy(a2+i,a1+i,1);
};

OR

memcpy(a2,a1,10);

atoi for strings only!!