Hex to Decimal, call of overload error

[bkovar]

on this line of my program:

sum=sum+(b[i]*pow(16,j));

the complier gives me a message that reads "call of overload 'pow(int, int&) is ambiguous. i have no idea what this error means so can someone help me? this program converts numbers to other forms, and this is in the hex to decimal part. here is the rest of the hex to decimal section of code:

case 4:
{
int n,i,j,b[100],sum=0;
char a[100];
cout<<"Enter number of digits in your hexadecimal number: ";
cin>>n;
cout<<"Enter hexadecimal number one character at a time: ";
for(i=1;i<=n;i++)
{
cin>>a[i];
}
for(i=1;i<=n;i++)
{
if(a[i]=='0')
{
b[i]=0;
}
if(a[i]=='1')
{
b[i]=1;
}
if(a[i]=='2')
{
b[i]=2;
}
if(a[i]=='3')
{
b[i]=3;
}
if(a[i]=='4')
{
b[i]=4;
}
if(a[i]=='5')
{
b[i]=5;
}
if(a[i]=='6')
{
b[i]=6;
}
if(a[i]=='7')
{
b[i]=7;
}
if(a[i]=='8')
{
b[i]=8;
}
if(a[i]=='9')
{
b[i]=9;
}
if(a[i]=='A'||a[i]=='a')
{
b[i]=10;
}
if(a[i]=='B'||a[i]=='b')
{
b[i]=11;
}
if(a[i]=='C'||a[i]=='c')
{
b[i]=12;
}
if(a[i]=='D'||a[i]=='d')
{
b[i]=13;
}
if(a[i]=='E'||a[i]=='e')
{
b[i]=14;
}
if(a[i]=='F'||a[i]=='f')
{
b[i]=15;
}
}
j=n-1;
for(i=1;i<=n;i++)
{
sum=sum+(b[i]*pow(16,j));
j--;
}
cout<<"The number in decimal is "<<sum<<endl;
}
break;

[Kiana]

sum = sum + (b[i] * pow(16, static_cast<double> (j)));

[bkovar]

thank you so much :) it works like a charm now