#include <iostream>
usingnamespace std;
int main()
{
char character;
int it;
if (character == 'b'){
for( it = 9; it > 1 ; it-- );
cout << "Variable is " << character << ' ' << it-- << endl;
cin >> character ;
}
Your error is in line 8
In for( it = 9; it > 1 ; it-- ); you have a semi colon after your loop causing it to end after the first iteration. Remove the semi colon and it should run how you want. Also, in line 9 cout << "Variable is " << character << ' ' << it-- << endl; you should remove it-- from your line and just replace it with it if your just trying to display the current iteration of the loop.
Also, just as a convention you should remodel your loop to look something like this
for(int i = 0; i < 9; i++)
But regardless, after you remove the semi colon it should run.
1 2 3 4
for(int i = 0; i < 9; i++){
cout << "Variable is " << character << ' ';
cin >> character ;
}
Solved that problem, thanks.
Now i inserted pointers to store the inputed value from c or a or d to a pointer then from pointer to put in variable "input" when i press b.
Now i want when i press c then when i press b to run the loop how many times i press c and b.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
#include <iostream>
usingnamespace std;
int main( )
{
char character, *input;
int i, it;
cin >> character;
if ( character == 'c' || 'a' || 'd') {
for( i = 1 ; i <= 9 && character!='b' ; i++ )
cin >> character
input=&character;}
if (character == 'b'){
for( it = 9; it > 1 ; it-- )
cout << "Variable is " << *input << ' ' << it << endl;
}
return 0;}
my output with this program is for example:
1 2 3 4 5 6 7 8 9 10 11 12 13 14
c
c
c
c
Variable is b 9
Variable is b 8
Variable is b 7
Variable is b 6
Variable is b 5
Variable is b 4
Variable is b 3
Variable is b 2
b
process returned 0 <0x0>...
i want to output this ->
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
d*
c**
a***
c****
d*****
b
Variable is d***** 9
b
Variable is c**** 8
b
Variable is a*** 7
b
Variable is c** 6
b
Variable is d* 5
c^
b
Variable is c^ 4 ...