what does this Task * mean？？？

[neyshule]

The code is like following， Task is a class，what does that （Task *） mean here？？

class InfiniteSource { ...
bool run_task(Task *t);
private:
Task _task;
};

InfiniteSource::InfiniteSource() : _task(this) {
}

int InfiniteSource::initialize(ErrorHandler *errh) {
ScheduleInfo::initialize_task(this, &_task, errh);
return 0;
}

bool InfiniteSource::run_task(Task *) {
Packet *p = ... generate packet ...;
output(0).push(p);
if (packets left to send)
_task.fast_reschedule();
return true; // the task did useful work
}

[Athar]

It's a pointer to a Task object.

[neyshule]

but why there is no parameter appeared？？？

[firedraco]

It means that although you pass a Task*, they never use it (and thus don't have to name it). Kind of dumb to have a parameter that you don't use though.

[neyshule]

If you don‘t use it，why bother pass it？？？？

[Athar]

Ask the one who wrote that code or check the documentation (if there is one) to see what the parameter's purpose is.
Something like this can happen when you override a virtual function, but don't care about its parameter. However, since InfiniteSource apparently doesn't inherit from anything, this doesn't seem to be the case here.