grep
I cant figure this out, new to Unix. Any help at all would be appreciated!
Suppose you were working a crossword puzzle and needed a 6-letter word beginning with 'b' (upper or lower-case) and with a lower-case 'e' as its third letter. What grep command would you use to list the words from /usr/dict/words that match this requirement?
Suppose you were working a crossword puzzle and needed a 6-letter word beginning with 'b' (upper or lower-case) and with a lower-case 'e' as its third letter. What grep command would you use to list the words from /usr/dict/words that match this requirement?
I'm a bit rusty with regular expressions, but how about
that is, IF there is always a newline after the end of the word.
grep '^[bB].e.\{3\}$' /usr/dict/words
|
that is, IF there is always a newline after the end of the word.
Last edited on
Bazzy, wouldn't that skip the requirement for the word to have exactly 6 letters?
... wait, mine does that too.
This should do the job.
... wait, mine does that too.
grep '^[bB].e[a-z]\{3\}$' /usr/dict/words
|
This should do the job.
Last edited on
Just a fix I just came up with, you should replace the dot after [bB] with [a-z] otherwise it will also match numbers and stuff, which is probably not what you want.
Topic archived. No new replies allowed.