How can a bash code do a return completely while in nested call

[marhuum]

How can a bash code do a return completely (as if it returns from main function) when it is being in a third nested function call, in order to get back to shell prompt at once ?

the function invocation is one which will fully shut down terminal if exit command is given.

tried so many times in vain, one of them:

c(){
local p
#...

[ "$p" = err ] && kill $TID

#...
}

b(){
#...
c
#...
}

a(){
export TID=$$
#...

b
#...
#...
}
Sincere help is thanked

[jonnin]

maybe you can exploit these ideas to exit the script?
http://www.davidpashley.com/articles/writing-robust-shell-scripts.html

[uplime]

Some of the advice on that site is good (you almost always want to quote your variables), but I'd be wary about most of it. Namely, the use of set -e, and this loop:

for file in $(find /var/www-tmp -type f -name "*.html"); do

Is there a reason you can't just do something like:

c() {
  # ...
}

b() {
  # ...
  c
  return
  # ...
}

a() {
  # ...
  b
  return
  # ...
}

You can also do something like

if c; then
  return
else
  # error
fi

Also, as a side note, there isn't really any reason to export TID, at least not in the code you've shown so far.